{"id":162,"date":"2025-01-06T11:00:41","date_gmt":"2025-01-06T05:30:41","guid":{"rendered":"https:\/\/samacheerkalvi.guide\/?p=162"},"modified":"2025-01-07T10:09:37","modified_gmt":"2025-01-07T04:39:37","slug":"samacheer-kalvi-9th-maths-guide-chapter-2-ex-2-2","status":"publish","type":"post","link":"https:\/\/samacheerkalvi.guide\/samacheer-kalvi-9th-maths-guide-chapter-2-ex-2-2\/","title":{"rendered":"Samacheer Kalvi 9th Maths Guide Chapter 2 Real Numbers Ex 2.2"},"content":{"rendered":"
Students can download Maths Chapter 2 Real Numbers Ex 2.2 Questions and Answers, Notes, Samacheer Kalvi 9th Maths Guide<\/a> Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.<\/p>\n Therefore, one Decimal<\/a> is equal to four hundred and thirty five decimal point six Square Feet (sq ft) in Online.<\/p>\n Question 1. (ii) -5\\(\\frac{3}{11}\\) = -5 + 0.272 = -5.272…….. (iii) \\(\\frac{22}{3}\\) = 7.333…….. (iv) \\(\\frac{327}{200}\\) = \\(\\frac{327}{2\u00d7100}\\) How to convert 1\/32 to decimal<\/a> form? … In the fraction 1\/32, 1 is the numerator and 32 is the denominator, the fraction bar means “divided by”.<\/p>\n Question 2. 9\/20 as a decimal<\/a> is 0.45<\/p>\n Question 3. That’s literally all there is to it! 1\/2 as a decimal<\/a> is 0.5.<\/p>\n Question 4. (ii) 2.327Tamilnadu Samacheer Kalvi 9th Maths Solutions Chapter 2 Real Numbers Ex 2.2<\/h2>\n
\nExpress the following rational numbers into decimal and state the kind of decimal expression.
\n(i) \\(\\frac{2}{7}\\)
\n(ii) -5\\(\\frac{3}{11}\\)
\n(iii) \\(\\frac{22}{3}\\)
\n(iv) \\(\\frac{327}{200}\\)
\nSolution:
\n
\n(i) \\(\\frac{2}{7}\\) = 0.2857142….
\n= 0.\\(\\overline {285714}\\)
\nNon-terminating and recurring decimal expansion.<\/p>\n<\/p>\n
\n
\n= -5.\\(\\overline {27}\\)
\nNon-terminating and recurring decimal expansion.<\/p>\n
\n
\n= 7.\\(\\overline {3}\\)
\nNon-terminating and recurring decimal expansion.<\/p>\n
\n
\n= \\(\\frac{3.27}{2}\\)
\n= 1.635
\nTerminating decimal expansion.<\/p>\n<\/p>\n
\nExpress \\(\\frac{1}{13}\\) in decimal form. Find the length of the period of decimals.
\nSolution:
\n
\n\\(\\frac{1}{13}\\) = 0.07692307
\n= 0.\\(\\overline {076923}\\)
\nLength of the period of decimal is 6.<\/p>\n
\nExpress the rational number \\(\\frac{1}{33}\\) in recurring decimal form by using the recurring decimal expansion of \\(\\frac{1}{11}\\). Hence write \\(\\frac{71}{33}\\) in recurring decimal form.
\nSolution:
\n
\n\\(\\frac{1}{11}\\) = 0.0909……… = 0.\\(\\overline {09}\\)
\n\u2234 \\(\\frac{1}{33}\\) = \\(\\frac{1}{3}\\) \u00d7 \\(\\frac{1}{11}\\)
\n= \\(\\frac{1}{3}\\) \u00d7 0.0909 ……..
\n= 0.0303 …… = 0.\\(\\overline {03}\\)
\n\\(\\frac{71}{33}\\) = 2\\(\\frac{5}{33}\\) = 2 + \\(\\frac{5}{33}\\) = 2 + 5 \u00d7 \\(\\frac{1}{33}\\)
\n= 2 + 5 \u00d7 0.\\(\\overline {03}\\)
\n2 + (5 \u00d7 0.030303 ……..)
\n2 + 0.151515 ………
\n2+ 0.\\(\\overline {15}\\)
\n2.\\(\\overline {15}\\)<\/p>\n<\/p>\n
\nExpress the following decimal expression into rational numbers.
\n(i) 0.24
\nSolution:
\nLet x = 0.242424 ………. \u2192(1)
\n100 x = 24.2424 ……… \u2192(2)
\n(2) – (1) \u21d2 100 x – x = 24.2424 ……….. (-)
\n\u00a00.2424<\/span> ……..
\n99 x = 24.0000
\nx = \\(\\frac{24}{99}\\)
\n(or)
\n\\(\\frac{8}{33}\\)<\/p>\n
\nSolution:
\nLet x = 2.327327327 ………. \u2192(1)
\n1000 x = 2327.327327 ……… \u2192(2)
\n(2) – (1) \u21d2 1000 x – x = 2327.327327 ……….. (-)
\n\u00a0 2.327327<\/span> ……..
\n999 x = 2325.000
\nx = \\(\\frac{2325}{999}\\)
\n(or)
\n\\(\\frac{775}{333}\\)<\/p>\n<\/p>\n