\nCombution<\/td>\n | Oxidation<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n <\/p>\n
IV. Answer in briefly :<\/span><\/p>\nQuestion 1. \nDifferentiate graphite and diamond. \nAnswer:<\/p>\n \n\n\nGraphite<\/td>\n | Diamond<\/td>\n<\/tr>\n | \nEach carbon atom has three covalent bonds.<\/td>\n | Each carbon atom has four covalent bonds.<\/td>\n<\/tr>\n | \nSoft, slippery to touch and opaque<\/td>\n | Hard, heavy and transparent<\/td>\n<\/tr>\n | \nIt has planar layers of hexagon units.<\/td>\n | It has tetrahedral units linked in three dimension<\/td>\n<\/tr>\n | \nIt is conductor of heat and electricity.<\/td>\n | It is non-conductor of heat and electricity<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n Question 2. \nWrite all possible isomers of C4<\/sub>H10<\/sub> \nAnswer: \n <\/p>\nQuestion 3. \nCarbon forms only covalent compounds. Why? \nAnswer: \nCarbon forms only covalent compounds because it has 4 electrons, in its.<\/p>\n <\/p>\n
Question 4. \nDefine Allotrophy. \nAnswer: \nAllotrophy is a property by which are element can exist in more than one form that are physically different and chemically similar.<\/p>\n Samacheer Kalvi 9th Science Guide Chapter 15 Carbon and its Compounds 1<\/p>\n Question 5. \nWhy are one-time use and throwaway plastics harmful? \nAnswer:<\/p>\n \n- Use and throwaway plastics cause short and long-term environmental damage.<\/li>\n
- Half of all the plastic made today is used for throwaway plastic items. These block drains and pollute water bodies.<\/li>\n
- One-time use plastic causes health problems for humans, plants and animals.<\/li>\n
- Some examples are plastic carry bags, cups, plates, straws, water pouches, cutlery and plastic sheets used for food wrapping.<\/li>\n<\/ol>\n
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V. Answer in detail :<\/span><\/p>\nQuestion 1. \nWhat is catenation? How does carbon form catenated compounds? \nAnswer: \nCatenation is binding of an element to itself or with other elements through covalent bonds to form open chain or closed chain compounds.<\/p>\n \n- Carbon is the most common element which undergoes catenation and long chain compounds.<\/li>\n
- Carbon atom links repeatedly to itself through covalent bond to form linear branched chain (or) ring structure<\/li>\n<\/ul>\n
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\n- This property of carbon itself is the reason for the presence of large number of organic carbon compounds.<\/li>\n
- So organic chemistry essentially deals with catenated carbon compounds.<\/li>\n
- Example: Starch and cellulose contain chains of hundreds of carbon atoms.<\/li>\n<\/ul>\n
Question 2. \nWhat are the chemical reactions of carbon? \nAnswer: \nElemental carbon undergoes no reaction at room temperature. \nOxidation : Carbon combines with oxygen to form its oxides such as carbon monoxide (CO) and carbon dioxide (CO2<\/sub>), with evolution of heat. Organic carbon compounds like hydrocarbon also undergo oxidation to form oxides and steam with evolution of heat and flame.<\/p>\nThis reaction is also called \u2018Combustion\u2019. \n <\/p>\n Reaction with Steam : Carbon reacts with steam to form carbon monoxide hydrogen. This mixture is called water gas. \nC(S)<\/sub> + H2<\/sub>O(g)<\/sub> \u2192 CO(g)<\/sub> + H2(g)<\/sub><\/p>\nReaction with Sulphur: With sulphur, carbon forms its disuiphide at high temperature. \nC(S)<\/sub> + S(g)<\/sub> \u2192 CS2(g)<\/sub><\/p>\nReaction with Metals : At elevated temperatures, carbon reacts with some metals like iron, tungsten, titanium, etc., to form their carbides \nW(S)<\/sub>+C(g)<\/sub> \u2192 WC(S)<\/sub><\/p>\n \nQuestion 3. \nName the three safer resin codes of plastics and describe their features. \nAnswer: \n <\/p>\n
VI. Higher Order Thinking Skills:<\/span><\/p>\nQuestion 1. \nWhy do carbon exist mostly in combined state? \nAnswer: \nCarbon is an element that can form many different compounds, as each carbon atom can form 4 chemical bonds with other atoms and because the carbon atom is just the right size to fit in comfortably as parts of very large molecules.<\/p>\n <\/p>\n
Question 2. \nWhen a carbon fuel burns in less aerated room, it is dangerous to stay there. Why? \nAnswer:<\/p>\n | |