{"id":981,"date":"2025-01-06T16:00:57","date_gmt":"2025-01-06T10:30:57","guid":{"rendered":"https:\/\/samacheerkalvi.guide\/?p=981"},"modified":"2025-01-07T10:08:09","modified_gmt":"2025-01-07T04:38:09","slug":"samacheer-kalvi-6th-maths-guide-term-3-chapter-1-ex-1-1","status":"publish","type":"post","link":"https:\/\/samacheerkalvi.guide\/samacheer-kalvi-6th-maths-guide-term-3-chapter-1-ex-1-1\/","title":{"rendered":"Samacheer Kalvi 6th Maths Guide Term 3 Chapter 1 Fractions Ex 1.1"},"content":{"rendered":"

Students can download Maths Chapter 1 Fractions Ex 1.1 Questions and Answers, Notes, Samacheer Kalvi 6th Maths Guide<\/a>\u00a0Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.<\/p>\n

Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 3 Chapter 1 Fractions Ex 1.1<\/h2>\n

Question 1.
\nFill in the blanks:
\n(i) 7\\(\\frac{3}{4}\\) + 6\\(\\frac{1}{2}\\) ………..
\n(ii) The sum of a whole number and a proper fraction is called ……….
\n(iii) 5\\(\\frac{1}{3}\\) – 3\\(\\frac{1}{2}\\) ………..
\n(iv) 8 \u00f7 \\(\\frac{1}{2}\\) ………..
\n(v) The number which has its own reciprocal is ……….
\nSolution:
\n\"Samacheer<\/p>\n

(ii) Mixed Fraction<\/p>\n

(iii) 5\\(\\frac{1}{3}\\) – 3\\(\\frac{1}{2}\\)
\n= \\(\\frac{16}{3}\\) – \\(\\frac{7}{2}\\) = \\(\\frac{32-21}{6}\\) = \\(\\frac{11}{6}\\)
\n= 1\\(\\frac{5}{6}\\)<\/p>\n

(iv) 8 \u00f7 \\(\\frac{1}{2}\\)
\n= 8 \u00d7 \\(\\frac{2}{1}\\)
\n= 16<\/p>\n

(v) 1<\/p>\n

\"Samacheer<\/p>\n

The first step would be to write the mix number 223 as an improper fraction.<\/a><\/p>\n

Question 2.
\nSay True or False
\n(i) 3\\(\\frac{1}{2}\\) can be written as 3 + \\(\\frac{1}{2}\\).
\n(ii) The sum of any two proper fractions is always an improper fraction.
\n(iii) The mixed fraction of \\(\\frac{13}{4}\\) is 3\\(\\frac{1}{4}\\).
\n(iv) The reciprocal of an improper fraction is always a proper fraction.
\n(v) 3\\(\\frac{1}{4}\\) \u00d7 3\\(\\frac{1}{4}\\) = 9\\(\\frac{1}{16}\\)
\nSolution:
\n(i) True
\n(ii) False
\n(iii) True
\n(iv) True
\n(v) False<\/p>\n

Question 3.
\nAnswer the following:
\n(i) Find the sum of \\(\\frac{1}{7}\\) and \\(\\frac{3}{9}\\).
\n(ii) What is the total of 3\\(\\frac{1}{3}\\) and 4\\(\\frac{1}{6}\\)?
\n(iii) Simplify: 1\\(\\frac{3}{5}\\)+5\\(\\frac{4}{7}\\).
\n(iv) Find the difference between \\(\\frac{8}{9}\\) and \\(\\frac{2}{7}\\)
\n(v) Subtract: 1\\(\\frac{3}{5}\\) from 2\\(\\frac{1}{3}\\).
\n(vi) Simplify: 7\\(\\frac{2}{7}\\) – 3\\(\\frac{4}{21}\\)
\nSolution:
\n(i) \\(\\frac{1}{7}\\) + \\(\\frac{3}{9}\\)
\n= \\(\\frac{9+21}{63}\\) = \\(\\frac{30}{63}\\) = \\(\\frac{10}{21}\\)<\/p>\n

\"Samacheer
\n\"Samacheer<\/p>\n

\"Samacheer<\/p>\n

Question 4.
\nConvert mixed fractions into improper fractions and vice versa:
\n(i) 3\\(\\frac{7}{18}\\)
\n(ii) \\(\\frac{99}{7}\\)
\n(iii) \\(\\frac{47}{6}\\)
\n(iv) 12\\(\\frac{1}{9}\\)
\nSolution:
\n(i) 3\\(\\frac{7}{18}\\) = \\(\\frac{61}{18}\\)
\n(ii) \\(\\frac{99}{7}\\) = 14\\(\\frac{1}{7}\\)
\n(iii) \\(\\frac{47}{6}\\) = 7\\(\\frac{5}{6}\\)
\n(iv) 12\\(\\frac{1}{9}\\) = \\(\\frac{109}{9}\\)<\/p>\n

Question 5.
\nMultiply the following:
\n(i) \\(\\frac{2}{3}\\) \u00d7 6
\n(ii) 8\\(\\frac{1}{3}\\) \u00d7 5
\n(iii) \\(\\frac{3}{8}\\) \u00d7 \\(\\frac{4}{5}\\)
\n(iv) 3\\(\\frac{5}{7}\\) \u00d7 1\\(\\frac{1}{13}\\)
\nSolution:
\n(i) \\(\\frac{2}{3}\\) \u00d7 6 = 4<\/p>\n

(ii) 8\\(\\frac{1}{3}\\) \u00d7 5
\n= \\(\\frac{25}{3}\\) \u00d7 5
\n= \\(\\frac{125}{3}\\)
\n= 41\\(\\frac{2}{3}\\)<\/p>\n

(iii) \\(\\frac{3}{8}\\) \u00d7 \\(\\frac{4}{5}\\)
\n= \\(\\frac{12}{40}\\) = \\(\\frac{3}{10}\\)<\/p>\n

(iv) 3\\(\\frac{5}{7}\\) \u00d7 1\\(\\frac{1}{13}\\)
\n= \\(\\frac{26}{7}\\) \u00d7 \\(\\frac{14}{13}\\)
\n= \\(\\frac{4}{1}\\)
\n= 4<\/p>\n

\"Samacheer<\/p>\n

Question 6.
\nDivide the following
\n(i) \\(\\frac{3}{7}\\) \u00f7 4
\n(ii) \\(\\frac{4}{3}\\) \u00f7 \\(\\frac{5}{9}\\)
\n(iii) 4\\(\\frac{1}{5}\\) \u00f7 3\\(\\frac{3}{4}\\)
\n(iv) 9\\(\\frac{2}{3}\\) \u00f7 1\\(\\frac{2}{3}\\)
\nSolution:
\n(i) \\(\\frac{3}{7}\\) \u00f7 4
\n= \\(\\frac{3}{7}\\) \u00d7 \\(\\frac{1}{4}\\) = \\(\\frac{3}{28}\\)<\/p>\n

(ii) \\(\\frac{4}{3}\\) \u00f7 \\(\\frac{5}{9}\\)
\n= \\(\\frac{4}{3}\\) \u00d7 \\(\\frac{9}{5}\\)
\n= \\(\\frac{12}{5}\\)
\n= 2\\(\\frac{2}{5}\\)<\/p>\n

\"Samacheer<\/p>\n

Question 7.
\nGowri purchased 3\\(\\frac{1}{2}\\) kg of tomatoes, \\(\\frac{3}{4}\\) kg of brinjal and 1\\(\\frac{1}{4}\\) kg of onion. What is the total weight of the vegetables she bought?
\nSolution:
\nTotal weight of vegetables bought
\n\"Samacheer<\/p>\n

\"Samacheer<\/p>\n

Question 8.
\nAn oil tin contains 3\\(\\frac{3}{4}\\) litres of oil of which 2\\(\\frac{1}{2}\\) litres of oil is used. How much oil is left over?
\nSolution:
\n\"Samacheer<\/p>\n

Question 9.
\nNilavan can walk 4\\(\\frac{1}{2}\\) km in an hour. How much distance will he cover in 3\\(\\frac{1}{2}\\) hours?
\nSolution:
\nDistance walked in an hour = 4\\(\\frac{1}{2}\\) km
\nDistance covered in 3\\(\\frac{1}{2}\\)
\nHours
\n\"Samacheer<\/p>\n

Question 10.
\nRavi bought a curtain of length 15\\(\\frac{3}{4}\\) m. If he cut the curtain into small pieces each of length 2\\(\\frac{1}{4}\\) m, then how many small curtains will he get?
\nSolution:
\nTotal length = 15\\(\\frac{3}{4}\\)
\nLength of the small pieces = 2\\(\\frac{1}{4}\\)
\nSmall curtains obtained
\n\"Samacheer
\n= 7<\/p>\n

\"Samacheer<\/p>\n

Objective Type Questions<\/span><\/p>\n

Question 11.
\nWhich of the following statement is incorrect?
\n(a) \\(\\frac{1}{2}\\) > \\(\\frac{1}{3}\\)
\n(b) \\(\\frac{7}{8}\\) > \\(\\frac{6}{7}\\)
\n(c) \\(\\frac{8}{9}\\) < \\(\\frac{9}{10}\\)
\n(d) \\(\\frac{10}{11}\\) > \\(\\frac{9}{10}\\)
\nSolution:
\n(d) \\(\\frac{10}{11}\\) > \\(\\frac{9}{10}\\)<\/p>\n

Question 12.
\nThe difference between \\(\\frac{3}{7}\\) and \\(\\frac{2}{9}\\) is
\n(a) \\(\\frac{13}{63}\\)
\n(b) \\(\\frac{1}{9}\\)
\n(c) \\(\\frac{1}{7}\\)
\n(d) \\(\\frac{9}{16}\\)
\nSolution:
\n(a) \\(\\frac{13}{63}\\)<\/p>\n

\"Samacheer<\/p>\n

Question 13.
\nThe reciprocal of \\(\\frac{53}{17}\\) is
\n(a) \\(\\frac{53}{17}\\)
\n(b) 5\\(\\frac{3}{17}\\)
\n(c) \\(\\frac{17}{53}\\)
\n(d) 3\\(\\frac{5}{17}\\)
\nSolution:
\n(c) \\(\\frac{17}{53}\\)<\/p>\n

Question 14.
\nIf \\(\\frac{6}{7}=\\frac{\\mathbf{A}}{49}\\), then the value of A is
\n(a) 42
\n(b) 36
\n(c) 25
\n(d) 48
\nSolution:
\n(a) 42
\nHint: \\(\\frac{6 \\times 49}{7}=42\\)<\/p>\n

\"Samacheer<\/p>\n

Question 15.
\nPugazh has been given four choices for his pocket money by his father. Which of the choices should he take in order to get the maximum money?
\n(a) \\(\\frac{2}{3}\\) of Rs 150
\n(b) \\(\\frac{3}{5}\\) of Rs 150
\n(c) \\(\\frac{4}{5}\\) of Rs 150
\n(d) \\(\\frac{1}{5}\\) of Rs 150
\nSolution:
\n(c) \\(\\frac{4}{5}\\) of Rs 150<\/p>\n","protected":false},"excerpt":{"rendered":"

Students can download Maths Chapter 1 Fractions Ex 1.1 Questions and Answers, Notes, Samacheer Kalvi 6th Maths Guide\u00a0Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams. Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 3 Chapter 1 Fractions Ex 1.1 …<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":false,"jetpack_social_options":{"image_generator_settings":{"template":"highway","enabled":false},"version":2}},"categories":[4],"tags":[],"class_list":["post-981","post","type-post","status-publish","format-standard","hentry","category-class-6"],"jetpack_publicize_connections":[],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/samacheerkalvi.guide\/wp-json\/wp\/v2\/posts\/981"}],"collection":[{"href":"https:\/\/samacheerkalvi.guide\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/samacheerkalvi.guide\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/samacheerkalvi.guide\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/samacheerkalvi.guide\/wp-json\/wp\/v2\/comments?post=981"}],"version-history":[{"count":1,"href":"https:\/\/samacheerkalvi.guide\/wp-json\/wp\/v2\/posts\/981\/revisions"}],"predecessor-version":[{"id":39657,"href":"https:\/\/samacheerkalvi.guide\/wp-json\/wp\/v2\/posts\/981\/revisions\/39657"}],"wp:attachment":[{"href":"https:\/\/samacheerkalvi.guide\/wp-json\/wp\/v2\/media?parent=981"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/samacheerkalvi.guide\/wp-json\/wp\/v2\/categories?post=981"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/samacheerkalvi.guide\/wp-json\/wp\/v2\/tags?post=981"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}