Category: Class 5

Students can download 5th Maths Term 3 Chapter 1 Geometry InText Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 1 Geometry InText Questions

Activity 1 (Text Book Page No. 2)

Write the perimeter of each figure:
Question 1.

Answer:
5 + 6 + 5 + 6 = 22 cm

Question 2.

Answer:
4 + 4 + 4 + 4 = 16 cm

Question 3.

Answer:
3 + 5 + 7 = 15 cm

Question 4.

Answer:
6 + 3 + 4 + 3 + 4 + 3 + 6 + 9 = 38 cm

Question 5.

Answer:
5 + 5 + 10 + 5 + 5 + 10 = 40 cm

Question 6.

Answer:
11 + 6 + 7 + 7 + 16 = 57 cm

Try This (Text Book Page No. 5)

If a square of side 1 cm is cut out of the corner of a larger square with side 4 cm (See the figure). What will be the perimeter of the remaining shape?
Answer:
Perimeter of the shape = 4 cm + 4 cm + 4 cm + 4cm = 16 cm
Perimeter of the remaining shape
= 4cm + 4cm + 3cm + 1cm + 1cm + 3cm
= 16cm

Activity 2 (Text Book Page No. 10)

Using the grid sheet find the area and perimeter of the rectangles and squares. Each square is 1 sq. cm.

Answer:

Students can download 5th Maths Term 3 Chapter 2 Numbers InText Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 2 Numbers InText Questions

Try This (Text Book Page.No 15)

Write down the estimated value of numbers and find their sum. Also, find the difference of their sum.

Answer:

Try This (Text Book Page.No 16)

Write down the estimated value of numbers and divide. Then find the difference between estimated value and actual value.

Answer:

Activity (Text Book Page.No 18)

A. Color the number’s row with the help of the following tips.

1. Orange colour to the prime number row.
2. Don’t colour to the odd number row.
3. Blue colour to 6 in multiples row.
4. Orange colour to the square number row.
5. Dont colour to the even number row.
6. Blue colour to 8 in multiples row.
Answer:

B. Let us fill the number wheel
Question 1.

Answer:

Question 2.

Answer:

Question 3.

Answer:

C. Complete the circle using the given four basic operators to get the number 20.

Answer:

D. Fill in the blanks
Question 1.
5, 10, 15, ——, 25
Answer:
20

Question 2.
30, 24, ——- ,126
Answer:
18

Question 3.
7, 9, 11, ——-, ——-, 17
Answer:
15

Question 4.
1, 4, 9, ——-, 25
Answer:
16

Question 5.
1, 4, 7, ——-,13, ——-, 19
Answer:
10, 16

E. Answer the following

Question 1.
If BOOK is 43,
Then PEN is ———-
Answer:
PEN = 16 + 5 + 14 = 35

Question 2.
If SCHOOL is 1938151512,
Then CLASS is ———–
Answer:
31211919

Question 3.
If BAG is 10,
Then BOOK is ———–
Answer:
2 + 15 + 15 + 11 = 43

Question 4.
If LION is 50.
Then TIGER is ———–
Answer:
20 + 9 + 7 + 5 + 18 = 59

Question 5.
If HEN is 8514,
Then COCK is ———–
Answer:
315311

Students can download 5th Maths Term 3 Chapter 2 Numbers Ex 2.1 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 2 Numbers Ex 2.1

Question 1.
Fill in the blanks

(i) Estimation of 27 to its nearest Tens place is ———–
Answer:
30

(ii) Estimation of 65 to its nearest Tens place is ———–
Answer:
70

(iii) The cost of 1kg pomegranate is? 93. Then the estimated cost is
Answer:
90

(iv) Estimation of 76 bananas to its nearest Tens place is ———–
Answer:
80

Question 2.
There are 27 girls and 38 boys in a class. Find the sum and estimate the sum to its nearest Tens place.
Ans:
Number of girls = 30
Number of boys = 40
Sum = 30 + 40
= 70

Question 3.
If the cost of a geometry box is ₹ 53 and the cost of a note book is ₹ 36, then estimate their cost to its nearest Tens place and find the sum. Also, find the difference between the estimated value and the actual value.
Answer:

Question 4.
If Kavitha has 93 pictures and she gave 42 pictures to her friend Neela, then estimate the picutres to its nearest Tens place and find their difference. Also, find the difference between actual value and the estimated value,
Answer:

Question 5.
The cost of a pen is ₹ 32. Find the cost of 6 pens and estimate it to its nearest Tens place.
Answer:
Cost of a pen = ₹ 32
Cost of 5 pens = 32 × 6 = 192.

Question 6.
Arun has ₹ 47, Raja has nearest Hundreds place. ₹ 54. Find the sum and estimate it to its nearest Hundreds place.
Answer:
Money A run has = Rs. 47
Money Raja has = Rs. 54
Sum = Rs. 47 + Rs 54 = 101
Sum ~ 100

Question 7.
There are 21 chocolate bars in a packet. Find the number of chocolate bars in 9 such packets and estimate it to its nearest Hundreds place.
Answer:
Number of chocolate bars in a packet = 21
Number of chocolate bars in 9 pockets = 21 × 9 = 189
Nearest hundred = 200

Question 8.
132 peanut candies are shared equally with 12 students. Find the share for one student and estimate it to its nearest Tens place.
Answer:
Number of peanut candies = 132
Number of students = 12
Number of candies one student get = 132 ÷ 12 = 11
Nearest tens = 10

Students can download 5th Maths Term 3 Chapter 1 Geometry Ex 1.2 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 1 Geometry Ex 1.2

Question 1.
The length of the side of each square is given below. Find its area.
(i) 10 metres
(ii) 5 cm
(iii) 15 metres
(iv) 16 cm
Answer:
(i) 10 metres
Area of the square = Length of a side × length of side
= 10 × 10 = 100 sq.m

(ii) 5 cm
Area of the square = Length of a side × length of side
= 5 × 5 = 25 sq.cm

(iii) 15 metres
Area of the square = Length of a side × length of side
= 15 ×15 = 225 sq.m

(iv) 16 cm
Area of the square = Length of a side × length of side
= 16 × 16 = 256 sq.cm

Question 2.
Find the area of the following rectangles.
(i) length = 6 cm and breadth = 3 cm
(ii) length = 7 in and breadth = 4
(iii) length = 8 cm and breadth = 5 cm
(iv) length = 9 m and breadth = 6 m
Answer:
(i) length = 6 cm and breadth = 3 cm
Area of the rectangle = Length × breadth
= 6 cm × 3 cm = 18cm ²

(ii) length = 7 in and breadth = 4
Area of the rectangle = Length × breadth
= 7 cm × 4 cm = 28 cm ²

(iii) length = 8 cm and breadth = 5 cm
Area of the rectangle = Length × breadth
= 8 cm × 5 cm = 40 cm ²

(iv) length = 9 m and breadth = 6 m
Area of the rectangle = Length × breadth
= 9 m × 6m = 54 m ²

Question 3.
If the cost of 1 sq.m of a plot is ₹ 800, then find the total cost of the plot that is 15 m long and 10 m breadth.
Answer:
Area of plot = length × breadth 15 × 10 = 150 sq.m
Cost of 1 sq.m of a plot of land = 800 rupees
Cost of a plot of land = 150 × 800 = 1,20,000 rupees.

Question 4.
The side of a square is 6 cm. The length of a rectangle is 10 cm and its breadth is 4 cm. Find the perimeter and area of both the square and rectangle.
Answer:
Perimeter of a square = 4 × length of a side = 4 × 6 cm: 24 cm
Area of a square = length of a side × length of a side
= 6 × 6 = 36cm²
Perimeter of a rectangle = 2 × length + 2 × breadth
= 2 × 10 + 2 × 4
= 20 + 8 = 28cm
Area of a rectangle = length × breadth
= 10 × 4 = 40 cm²

Question 5.
What will be the labour cost of laying the floor of an assembly hall which is 14 m long and 10 m breadth if the cost of laying is 60 per sq.m?
Answer:
Area of a rectangle = length × breadth
= 14 × 10 = 140 cm²
Cost of laying 1 sq.m = 60 rupees
Cost of laying the floor = 140 × 60 = 8400 rupees

Students can download 5th Maths Term 2 Chapter 6 Information Processing Ex 6.1 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 6 Information Processing Ex 6.1

Question 1.
Choose the correct answer

(i) Which shape have 6 triangles?
(a)

(b)

(c)

(d)

Answer:
(b)

(ii) Find which garland has made up of 12 beads?
(a)

(b)

(c)

(d)

Answer:
(c)

Question 2.
Answer the following
(i)

4, 4, 3, 5, 4, 4, _______, _______, _______, _______, _______, _______,
Answer:
4, 4, 3, 5, 4, 4, 3, 5, 4, 4, 3, 5 [Number of sides]

(ii) 1, 1, 2, 3, 5, 8, _______, _______, _______, _______, _______, _______,
Answer:
1, 1, 2, 3, 5, 8, 13, 21, 34, 55
Hint:
5 + 8 = 13
13 + 8 = 21
21 + 13 = 34
34 + 21 = 55

Question 3.


Answer:
3 + 4 + 5 + 3 – 4
= 15 – 4
= 11

Answer:
44 – 33 = 11

Students can download 5th Maths Term 2 Chapter 6 Information Processing InText Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 6 Information Processing InText Questions

Try This (Text Book Page No.50)

How many squares are there?

Answer:
6 squares

Activity (Text Book Page No.50)

Answer:

Activity (Text Book Page No.50)

The following shapes are drawn instead of numbers 0, 1, 2, 3, 4, 5. Shall we find the number of each shapes.


Answer:

Activity (Text Book Page No.51)

(i) Number of circles _________
Answer:
9

(ii) Number of Triangles _________
Answer:
18

(iii) Number of Squares _________
Answer:
2

Try These (Text Book Page No.51)

How many rectangles are there in this diagram?

Answer:
24

Students can download 5th Maths Term 2 Chapter 5 Interconcept InText Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 5 Interconcept InText Questions

Activity (Text Book Page No.41)

Question 1.
Write distance, bus fares and travel time from your town to the nearest cities:

Distance, Time and money are interrelated in our daily life situations. Can you discuss and complete the table given below?

Answer:

Question 2.
Distances are given below from Chennai to Kanyakumari

City	Distance [KM]
Chennai	0 km
Tambaram	35 km
Tindivanam	128 km
Villupuram	172 km
Trichy	332 km
Madurai	462 km
Virudunagar	520 km
Tirunelveli	624 km
Kanya Kumari	707 km

Complete the following:

1. The distance between Chennai to Tindivanam ______
Answer:
128 km

2. The distance between Chennai to Villupuram ______
Answer:
172 km

3. The distance between Chennai to Trichy ______
Answer:
332 km

4. The distance between Trichy to Madurai ______
Answer:
462 – 332 = 130 km

5. The distance between Madurai to Tirunelveli ______
Answer:
624 – 462 = 162 km

6. The distance between Chennai to Kanyakumari ______
Answer:
707 km

7. The distance between Trichy to Kanyakumari ______
Answer:
707 – 332 = 375 km

8. The distance between Tindivanam to Tirunelveli ______
Answer:
624 – 128 = 496 km

9. The distance between Chennai to Madurai _____
Answer:
462 km

10. Which is the longest distance? Chennai to Trichy/Chennai to Madurai? ______
Answer:
Chennai to Madurai

Activity (Text Book Page No.43)

Question 1.
The distance between planets and sun

Planets	Distance from sun (KM)
Mercury	57909175
Venus	108200000
Earth	149600011
Mars	227940000
Jupiter	778333000
Saturn	1429400000
Uranus	2870990000
Neptune	4504300000

Answer the following from the given table:

1.The distance between Earth and Sun is _________ .
Answer:
149600011

2. _________ Planet is in the longest distance from the sun.
Answer:
Neptune

3. The Nearest Planet to Sun is _________ .
Answer:
Mercury

4. Arrange the planets in ascending order depending upon the Planets distance from the sun.
Answer:

• Mercury
• Venus
• Earth
• Mars
• Jupiter
• Saturn
• Uranus
• Neptune

5. Arrange the planets in descending order depending upon the Planets distance from the sun.
Answer:

• Neptune
• Uranus
• Saturn
• Jupiter
• Mars
• Earth
• Venus
• Mercury

Students can download 5th Maths Term 2 Chapter 5 Interconcept Ex 5.4 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 5 Interconcept Ex 5.4

Question 1.
Answer the following
(i) 3 Km 500 m = _______
Answer:
3 Km 500 m = 3 + 500 × \(\frac { 1 }{ 1000 }\)
= 3 + \(\frac { 1 }{ 2 }\) = 3\(\frac { 1 }{ 2 }\) km

(ii) 25 Km 250 m = _______
Answer:
25 Km 250 m = 25 + 250 × \(\frac { 1 }{ 1000 }\)
= 25 + \(\frac { 1 }{ 4 }\) = 25\(\frac { 1 }{ 4 }\) km

(iii) 17 Km 750 m = _______
Answer:
17 Km 750 m = 17 + 750 × \(\frac { 1 }{ 1000 }\)
= 17 + \(\frac { 3 }{ 4 }\) = 17\(\frac { 3 }{ 4 }\) km

(iv) 35 Km 250 m = _______
Answer:
35 Km 250 m = 35 + 250 × \(\frac { 1 }{ 1000 }\)
= 35 + \(\frac { 1 }{ 4 }\) = 35\(\frac { 1 }{ 4 }\) km

(v) 45 Km 750 m = _______
Answer:
45 Km 750 m = 45 + 750 × \(\frac { 1 }{ 1000 }\)
= 45 + \(\frac { 3 }{ 4 }\) = 45\(\frac { 3 }{ 4 }\) km

Question 2.
Convert into Hours: [In fraction]
(i) 10 minutes
Answer:
10 minutes = 10 × \(\frac { 1 }{ 60 }\)
= \(\frac { 1 }{ 6 }\) hours

(ii) 25 minutes
Answer:
25 minutes = 25 × \(\frac { 1 }{ 60 }\)
= \(\frac { 5 }{ 12 }\) hours

(iii) 36 minutes
Answer:
36 minutes = 36 × \(\frac { 1 }{ 60 }\)
= \(\frac { 3 }{ 5 }\) hours

(iv) 48 minutes
Answer:
48 minutes = 48 × \(\frac { 1 }{ 60 }\)
= \(\frac { 4 }{ 5 }\) hours

(v) 50 minutes
Answer:
50 minutes = 50 × \(\frac { 1 }{ 60 }\)
= \(\frac { 5 }{ 6 }\) hours

Question 3.
Convert into minutes:
(i) \(\frac { 5 }{ 6 }\) Hour
Answer:
\(\frac { 5 }{ 6 }\) Hour = \(\frac { 5 }{ 6 }\) × 60
= 50 minutes

(ii) \(\frac { 8 }{ 10 }\) Hour
Answer:
\(\frac { 8 }{ 10 }\) Hour = \(\frac { 8 }{ 10 }\) × 60
= 48 minutes

(iii) \(\frac { 4 }{ 6 }\) Hour
Answer:
\(\frac { 4 }{ 6 }\) Hour = \(\frac { 4 }{ 6 }\) × 60
= 40 minutes

(iv) \(\frac { 5 }{ 10 }\) Hour
Answer:
\(\frac { 5 }{ 10 }\) Hour = \(\frac { 5 }{ 10 }\) × 60
= 30 minutes

(v) \(\frac { 6 }{ 10 }\) Hour
Answer:
\(\frac { 6 }{ 10 }\) Hour = \(\frac { 6 }{ 10 }\) × 60
= 36 minutes

Question 4.
Match the following:

Answer:

Question 5.
Write the \(\frac { 1 }{ 4 }\), \(\frac { 1 }{ 2 }\) and \(\frac { 3 }{ 4 }\) parts of the following
(i) ₹ 200
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 200 = \(\frac { 1 }{ 4 }\) × 200 = \(\frac { 200 }{ 4 }\) = ₹ 50
\(\frac { 1 }{ 2 }\) part of ₹ 200 = \(\frac { 1 }{ 2 }\) × 200 = \(\frac { 200 }{ 2 }\) = ₹ 100
\(\frac { 3 }{ 4 }\) part of ₹ 200 = \(\frac { 3 }{ 4 }\) × 200 = \(\frac { 600 }{ 4 }\) = ₹ 150

(ii) ₹ 10,000
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 10,000 = \(\frac { 1 }{ 4 }\) × 10,000 = \(\frac { 10000 }{ 4 }\) = ₹ 2500
\(\frac { 1 }{ 2 }\) part of ₹ 10,000 = \(\frac { 1 }{ 2 }\) × 10,000 = \(\frac { 10000 }{ 2 }\) = ₹ 5000
\(\frac { 3 }{ 4 }\) part of ₹ 10,000 = \(\frac { 3 }{ 4 }\) × 10,000 = \(\frac { 30000 }{ 4 }\) = ₹ 7500

(iii) ₹ 8,000
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 8,000 = \(\frac { 1 }{ 4 }\) × 8,000 = \(\frac { 8000 }{ 4 }\) = ₹ 2000
\(\frac { 1 }{ 2 }\) part of ₹ 8,000 = \(\frac { 1 }{ 2 }\) × 8,000 = \(\frac { 8000 }{ 2 }\) = ₹ 4000
\(\frac { 3 }{ 4 }\) part of ₹ 8,000 = \(\frac { 3 }{ 4 }\) × 8,000 = \(\frac { 24000 }{ 4 }\) = ₹ 6000

(iv) ₹ 24,000
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 24,000 = \(\frac { 1 }{ 4 }\) × 24,000 = \(\frac { 24000 }{ 4 }\) = ₹ 6000
\(\frac { 1 }{ 2 }\) part of ₹ 24,000 = \(\frac { 1 }{ 2 }\) × 24,000 = \(\frac { 24000 }{ 2 }\) = ₹ 12000
\(\frac { 3 }{ 4 }\) part of ₹ 24,000 = \(\frac { 3 }{ 4 }\) × 24,000 = \(\frac { 72000 }{ 4 }\) = ₹ 18000

(iv) ₹ 50,000
Answer:
\(\frac { 1 }{ 4 }\) part of ₹ 50,000 = \(\frac { 1 }{ 4 }\) × 50,000 = \(\frac { 50000 }{ 4 }\) = ₹ 12500
\(\frac { 1 }{ 2 }\) part of ₹ 50,000 = \(\frac { 1 }{ 2 }\) × 50,000 = \(\frac { 50000 }{ 2 }\) = ₹ 25000
\(\frac { 3 }{ 4 }\) part of ₹ 50,000 = \(\frac { 3 }{ 4 }\) × 50,000 = \(\frac { 150000 }{ 4 }\) = ₹ 37500

Students can download 5th Maths Term 2 Chapter 5 Interconcept Ex 5.3 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 5 Interconcept Ex 5.3

Question 1.
Answer the following

Answer:

Question 2.
Sneha spent ₹ 7 per Km for a trip and she travelled 850km. How much is the total cost of the trip?
Answer:
Cost per kilometer is ₹ 7
Cost for 850 km = 850 × ₹ 7
= ₹ 5950

Question 3.
Prabhu spent ₹ 9 per Km for o trip and he travelled 580km. How much is the total cost of the trip?
Answer:
Cost per kilometer is ₹ 9
Cost for 850 km = 580 × ₹ 9
= ₹ 5220

Students can download 5th Maths Term 2 Chapter 5 Interconcept Ex 5.2 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 2 Chapter 5 Interconcept Ex 5.2

Question 1.
Answer the following

Answer:

Question 2.
Wilson reached 240 Km at the speed of 60 Km/hour. How muc time did he travelled?
Answer:

Question 3.
Anbarasan travelled 350 Km at the speed of 70 Km/hour. Find the time taken for his travel.
Answer:

Question 4.
Nazar travelled 360 Km at the speed of 90 Km/hour. Find the time taken for his travel.
Answer:

Question 5.
Fathima reached 480 Km at the speed of 120 Km/hour. How much time did she travelled?
Answer: