Category: Class 5

Students can download 5th Maths Term 3 Chapter 6 Fractions 6.1 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 6 Fractions 6.1

Question 1.
Write the fraction shown by the shaded parts.
(i)

Answer:
\(\frac { 5 }{ 12 }\)

(ii)

Answer:
\(\frac { 2 }{ 6 }\)

(iii)

Answer:
\(\frac { 3 }{ 9 }\)

Question 2.
Write the fractions for the following and find the numerator and the denominator.
(i) Sheeki got 12 marks out of 20 marks in science.
Answer:
\(\frac { 12 }{ 20 }\); Numerator = 12; Denominator = 20

(ii) Six fruits are rotten out of forty fruits in a basket.
Answer:
\(\frac { 6 }{ 40 }\); Numerator = 6; Denominator = 40

(iii) In a colony of 50 houses. 17 houses are not occupied.
Answer:
\(\frac { 17 }{ 50 }\); Numerator = 17; Denominator = 50

Question 3.
Find out which is greater in the following fractions.
(i) \(\frac { 5 }{ 12 }\) and \(\frac { 7 }{ 12 }\)
(ii) \(\frac { 22 }{ 48 }\) and \(\frac { 17 }{ 48 }\)
(iii) \(\frac { 11 }{ 56 }\) and \(\frac { 27 }{ 56 }\)
Answer:
(i) \(\frac { 5 }{ 12 }\) and \(\frac { 7 }{ 12 }\)
5 < 7
∴ \(\frac { 5 }{ 12 }\) < \(\frac { 7 }{ 12 }\)
\(\frac { 7 }{ 12 }\) is greater

(ii) \(\frac { 22 }{ 48 }\) and \(\frac { 17 }{ 48 }\)
22 > 17
∴ \(\frac { 22 }{ 48 }\) > \(\frac { 17 }{ 48 }\)
\(\frac { 22 }{ 48 }\) is greater.

(iii) \(\frac { 11 }{ 56 }\) and \(\frac { 27 }{ 56 }\)
11 < 27
∴ \(\frac { 11 }{ 56 }\) < \(\frac { 27 }{ 56 }\)
\(\frac { 27 }{ 56 }\)
11 < 27 is greater

Question 4.
Which is smaller in the following fraction?
(i) \(\frac { 10 }{ 42 }\) and \(\frac { 21 }{ 42 }\)
(ii) \(\frac { 31 }{ 37 }\) and \(\frac { 15 }{ 37 }\)
Answer:
(i) \(\frac { 10 }{ 42 }\) and \(\frac { 21 }{ 42 }\)
10 < 21
\(\frac { 10 }{ 42 }\) < \(\frac { 21 }{ 42 }\)
\(\frac { 10 }{ 42 }\) is smaller

(ii) \(\frac { 31 }{ 37 }\) and \(\frac { 15 }{ 37 }\)
15 < 31
\(\frac { 31 }{ 37 }\) < \(\frac { 15 }{ 37 }\)
\(\frac { 15 }{ 37 }\) is smaller

Students can download 5th Maths Term 3 Chapter 6 Fractions 6.5 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 6 Fractions 6.5

Question 1.
Add the following fractions
(i) \(\frac{1}{5}\) + \(\frac{3}{5}\)
Answer:
\(\frac{1}{5}+\frac{3}{5}=\frac{1+3}{5}=\frac{4}{5}\)

(ii) \(\frac{1}{7}\) + \(\frac{3}{7}\)
Answer:
\(\frac{1}{7}+\frac{3}{7}=\frac{1+3}{7}=\frac{4}{7}\)

(iii) \(\frac{5}{12}\) + \(\frac{2}{12}\)
Answer:
\(\frac{5}{12}+\frac{2}{12}=\frac{5+2}{12}=\frac{7}{12}\)

(iv) \(\frac{3}{9}\) + \(\frac{7}{9}\)
Answer:
\(\frac{3}{9}+\frac{7}{9}=\frac{3+7}{9}=\frac{10}{9}\)

(v) \(\frac{2}{15}\) + \(\frac{3}{15}\)
Answer:
\(\frac{2}{15}+\frac{3}{15}=\frac{2+3}{15}=\frac{5}{15}\)

(vi) \(\frac{2}{7}\) + \(\frac{1}{7}\) + \(\frac{3}{7}\)
Answer:
\(\frac{2}{7}+\frac{1}{7}+\frac{3}{7}=\frac{2+1+3}{7}=\frac{6}{7}\)

(vii) \(\frac{3}{10}\) + \(\frac{5}{10}\) + \(\frac{2}{10}\)
Answer:
\(\frac{3}{10}+\frac{5}{10}+\frac{2}{10}=\frac{3+5+2}{10}=\frac{10}{10}=1\)

(viii) \(\frac{2}{9}\) + \(\frac{1}{9}\)
Answer:
\(\frac{2}{9}+\frac{1}{9}=\frac{2+1}{9}=\frac{3}{9}\)

(ix) \(\frac{3}{8}\) + \(\frac{2}{8}\)
Answer:
\(\frac{3}{8}+\frac{2}{8}=\frac{3+2}{8}=\frac{5}{8}\)

Question 2.
Mother gave \(\frac{2}{8}\) of guava to Meena and \(\frac{3}{8}\) of guava to Geetha. How many parts of the guava did she give them altogether?
Answer:
Meena get = \(\frac{2}{8}\)
Geeta get = \(\frac{3}{8}\)
Sum = \(\frac{2}{8}\) + \(\frac{3}{8}\) = \(\frac{5}{8}\)

Question 3.
The girls of Std V cleaned \(\frac{3}{5}\) of a field, while the boys cleaned \(\frac{1}{5}\) part of the field. What part of the field was cleaned altogether?
Answer:
Girls cleaned = \(\frac{3}{5}\)
Boys cleaned = \(\frac{1}{5}\)
Sum = \(\frac{3}{5}+\frac{1}{5}=\frac{4}{5}\)

Students can download 5th Maths Term 3 Chapter 6 Fractions 6.4 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 6 Fractions 6.4

Question 1.
Write the proper symbol from <, >, or = in the box
(i) \(\frac{3}{5}\) ___ \(\frac{2}{5}\)
Answer:
\(\frac{3}{5}\)   >    \(\frac{2}{5}\)

(ii) \(\frac{2}{8}\) ___ \(\frac{1}{8}\)
Answer:
\(\frac{2}{8}\)    >     \(\frac{1}{8}\)

(iii) \(\frac{2}{11}\) ___ \(\frac{10}{11}\)
Answer:
\(\frac{2}{11}\)    <     \(\frac{10}{11}\)

(iv) \(\frac{3}{15}\) ___ \(\frac{10}{30}\)
Answer:
\(\frac{3}{15}=\frac{3 \times 2}{15 \times 2}=\frac{6}{30}\)
\(\frac{6}{30}\)   <    \(\frac{10}{30}\)
\(\frac{3}{15}\)   <    \(\frac{10}{30}\)

(v) \(\frac{3}{8}\) ___ \(\frac{3}{7}\)
Answer:
\(\frac{3}{8}=\frac{3 \times 7}{8 \times 7}=\frac{21}{56}\)
\(\frac{3}{7}=\frac{3 \times 8}{7 \times 8}=\frac{24}{56}\)
\(\frac{21}{56}\)   <    \(\frac{24}{56}\)
\(\frac{3}{8}\)   <    \(\frac{3}{7}\)

(vi) \(\frac{4}{7}\) ___ \(\frac{4}{11}\)
Answer:
\(\frac{4}{7}=\frac{4 \times 11}{7 \times 11}=\frac{44}{77}\)
\(\frac{4}{11}=\frac{4 \times 7}{11 \times 7}=\frac{28}{77}\)
\(\frac{44}{77}\)    >    \(\frac{28}{77}\)
\(\frac{4}{7}\)    >    \(\frac{4}{11}\)

(vii) \(\frac{5}{12}\) ___ \(\frac{1}{6}\)
Answer:
\(\frac{1}{6}=\frac{1 \times 2}{6 \times 2}=\frac{2}{12}\)
\(\frac{5}{12}\)    >    \(\frac{2}{12}\)
\(\frac{5}{12}\)    >    \(\frac{1}{6}\)
\(\frac{3}{7}\)   <    \(\frac{5}{9}\)

(viii) \(\frac{4}{9}\) ___ \(\frac{4}{9}\)
Answer:
\(\frac{4}{9}\) = \(\frac{4}{9}\)

(ix) \(\frac{3}{7}\) ___ \(\frac{5}{9}\)
Answer:
\(\frac{3}{7}=\frac{3 \times 9}{7 \times 9}=\frac{27}{63}\)
\(\frac{5}{9}=\frac{5 \times 7}{9 \times 7}=\frac{35}{63}\)
\(\frac{27}{63}\)   <    \(\frac{35}{63}\)

(x) \(\frac{4}{11}\) ___ \(\frac{1}{5}\)
Answer:
\(\frac{4}{11}=\frac{4 \times 5}{11 \times 5}=\frac{20}{55}\)
\(\frac{1}{5}=\frac{1 \times 11}{5 \times 11}=\frac{11}{55}\)
\(\frac{20}{55}\)    >    \(\frac{11}{55}\)
\(\frac{4}{11}\)    >    \(\frac{1}{5}\)

Students can download 5th Maths Term 3 Chapter 6 Fractions 6.2 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 6 Fractions 6.2

Question 1.
Write the suitable number in the box.
(i)

Answer:

(ii)

Answer:

(iii)

Answer:

(iv)

Answer:

(v)

Answer:

(vi)

Answer:

(vii)

Answer:

(viii)

Answer:

Question 2.
Find an equivalent fraction with denominator 18 for each of the following fractions \(\frac{1}{2}, \frac{2}{3}, \frac{4}{6}, \frac{2}{9}, \frac{7}{9}, \frac{5}{3}\)
Answer:
\(\frac{1}{2}=\frac{1 \times 9}{2 \times 9}=\frac{9}{18}\)
\(\frac{2}{3}=\frac{2 \times 6}{3 \times 6}=\frac{12}{18}\)
\(\frac{4}{6}=\frac{3 \times 4}{3 \times 6}=\frac{12}{18}\)
\(\frac{2}{9}=\frac{2 \times 2}{9 \times 2}=\frac{4}{18}\)
\(\frac{7}{9}=\frac{7 \times 2}{9 \times 2}=\frac{14}{18}\)
\(\frac{5}{3}=\frac{5 \times 6}{3 \times 6}=\frac{30}{18}\)

Question 3.
Find an equivalent fraction with denominator 5 for each of the following fractions \(\frac{6}{15}, \frac{10}{25}, \frac{12}{30}, \frac{6}{10}, \frac{21}{35}\)
Answeer:
\(\frac{6}{15}=\frac{6 \div 3}{15 \div 3}=\frac{2}{5}\)
\(\frac{10}{25}=\frac{10 \div 5}{25 \div 5}=\frac{2}{5}\)
\(\frac{12}{30}=\frac{12 \div 6}{30 \div 6}=\frac{2}{5}\)
\(\frac{6}{10}=\frac{6 \div 2}{10 \div 2}=\frac{3}{5}\)
\(\frac{21}{35}=\frac{21 \div 7}{35 \div 7}=\frac{3}{5}\)

Students can download 5th Maths Term 3 Chapter 5 Money Ex 5.1 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 5 Money Ex 5.1

Question 1.
Fill in the blanks
(i) ₹ 35,50 + ₹ 4.50 = ______

Answer:
₹ 40.00

(ii) ₹ 7500 + ₹ 3000 = ______

Answer:
₹ 10500

(iii) ₹ 1000 – ₹ 230 = ______

Answer:
₹ 770.00

(iv) ₹ 75.50 – ₹ 30.25 = ______

Answer:
₹ 45.25

Question 2.
Match the following

(i) ₹ 950.50 + ₹ 350	(a) ₹ 399.50
(ii) ₹ 8000 – ₹ 3500	(b) ₹ 91.25
(iii) ₹ 50.70 + ₹ 40.00	(c) ₹ 1300.50
(iv) ₹ 750 – ₹ 350.00	(d) ₹ 4500

Answer:

(i) ₹ 950.50 + ₹ 350	(c) ₹ 1300.50
(ii) ₹ 8000 – ₹ 3500	(d) ₹ 4500
(iii) ₹ 50.70 + ₹ 40.00	(b) ₹ 91.25
(iv) ₹ 750 – ₹ 350.00	(a) ₹ 399.50

Question 3.
Add the following
(i) ₹ 8987.75 + ₹ 9565.50 + ₹ 7693.50
(ii) ₹ 29763.50 + ₹ 95675.50 + ₹ 4973.50
(iii) ₹ 9978.75 + ₹ 7695.50 + ₹ 635.00
Answer:
(i) ₹ 8987.75 + ₹ 9565.50 + ₹ 7693.50

(ii) ₹ 29763.50 + ₹ 95675.50 + ₹ 4973.50

(iii) ₹ 9978.75 + ₹ 7695.50 + ₹ 635.00

Question 4.
Subtract the following
(i) ₹1985 – ₹ 798.25
(ii) ₹ 688 – ₹ 215
(iii) ₹ 49689 – ₹ 33462.50
Answer:
(i) ₹1985 – ₹ 798.25

(ii) ₹ 688 – ₹ 215

(iii) ₹ 49689 – ₹ 33462.50

Question 5.
Arun purchased gold coins in different weights in a Jewellery shop. The price of the gold coins were ₹ 18965.75, ₹ 26998.00 and ₹ 3589.50 respectively. Find the total price of the gold coins.
Answer:

Question 6.
In a textiles shop, father, mother, son and daughter were purchasing clothes. The price of each of their clothes were ₹ 8950, ₹ 14875, ₹ 7895 and ₹ 9780 respectively. Find the total cost of their clothes.
Answer:

Question 7.
A farmer wanted to buy a tractor. The price of the tractor was ₹ 6,72,598, but he had only ₹ 2,86,760. How much more amount was required to buy the tractor?
Answer:

Question 8.
A man had ₹ 17,246 in his savings account. If he had taken ₹ 8,891 to pay for house rent, then how much amount was left in his savings account?
Answer:

Students can download 5th Maths Term 3 Chapter 4 Algebra Ex 4.2 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 4 Algebra Ex 4.2

Question 1.
Say whether true or false

(i) (23 + 4) = (4 + 23)
Hint: 27 = 27
Answer:
True

(ii) (9 + 4) > 12
Hint: 13 > 12
Answer:
True

(iii) (9 + 4) < 12
Hint: 13 < 12
Answer:
False

(iv) 11 > 121
Answer:
False

(v) 142 < 142
Answer:
False

(vi) 112 = 112
Answer:
True

(vii) (6 × 5) (32 – 2)
Hint: 30 = 30
Answer:
True

(viii) \(\frac { 49 }{ 7 }\) > 7
Hint: \(\frac { 49 }{ 7 }\) = 7
Answer:
False

(ix) (4 × 3) = (3 × 4)
Hint: 4 × 3 = 12 ;
3 × 4 = 12
Answer:
True

(x) (21 + 0) = 21
Answer:
True

Question 2.
Fill in the blanks with the right symbol (<, > or =).
(i) (54 ÷ 9) ___ (8 – 3)
Answer:
54 ÷ 9 = 6
8 – 3 = 5
6 > 5
(54 ÷ 9) > 8 – 3

(ii)(6 + 2) ___ (4 × 2)
Answer:
6 + 2 = 8
4 × 2 = 8
8 = 8
(6 + 2) = (4 × 2)

(iii) (10 × 2) ____ (15 + 20)
Answer:
10 × 2 = 20
15 + 20 = 35
20 < 35
10 × 2 < 15 + 20

Question 3.
Fill in the blanks in the expressions with the suitable number.
(i) (1 × 9) = (___ × 1)
Answer:
(1 × 9) = (9 × 1)

(ii) (6 × 3) > (8 × ___)
Answer:
6 × 3 = 18
8 × 2 = 16
18 > 16
6 × 3 > (8 × 2)

(iii) (36 ÷ 6) < (___ × 7)
Answer:
36 ÷ 6 = 6
1 × 7 = 7
6 < 7
(36 ÷ 6) < 1 × 7

(iv) (0 + 2) > (7 × ____)
Answer:
(0 + 2) = 2
7 × 0 = 0
2 > 0
(0 + 2) > (7 × 0)

(v) (42 ÷ 7) = (4 + ____)
Answer:
(42 ÷ 7) = 6
4 + 2 = 6
(42 ÷ 7) = (4 + 2)

(vi) (6 – ___) < (1 + 2)
Answer:
6 – 4 = 2
1 + 2 = 3
2 < 3
(6 – 3) < (1 + 2)

Students can download 5th Maths Term 3 Chapter 4 Algebra Ex 4.1 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 4 Algebra Ex 4.1

Question 1.
Using brackets, write three pairs of numbers whose sum is 12. Use them to write three equalities.
Answer:
(a)
(i) (7 + 5)
(ii) (8 + 4)
(iii) (6 + 6)

(b)
(i) 7 + 5 = 8 + 4
(ii) 7 + 5 = 6 + 6
(iii) 8 + 4 = 6 + 6

Question 2.
Find four pairs of numbers, one for each of addition, subtractions multiplication and division that make the number 16. Write the equalities for each of them.
Answer:
(a)
(i) (12 + 4)
(ii) (20 – 4)
(iii) (8 × 2)
(iv) (32 ÷ 2)

(b)
(i) 12 + 4 = 8 + 6
(ii) 20 – 4 = 18 – 2
(iii) 8 × 2 = 4 × 4
(iv) 32 ÷ 2 = 48 ÷ 3

Students can download 5th Maths Term 3 Chapter 3 Measurements InText Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 3 Measurements InText Questions

Activity 2 (Text Book Page N0.24)

Take some water in a beaker and mark its level.
Take a solid, that is, potato and immerse it in the beaker containing water.
What do you observe?

Answer:
The Water level increases

Activity 4 (Text Book Page N0.26)

We shall follow the method of unit cubes to calculate or find the volume of the objects given below. The dimensions of the objects are mentioned.

Answer:
Volume of Book = 10 × 6 × 1 = 60 unit cubes
Volume of pencil Box = 6 × 2 × 1 = 12 unit cubes

Students can download 5th Maths Term 3 Chapter 3 Measurements Ex 3.2 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 3 Measurements Ex 3.2

Question 1.
Volume of regular solids such as cube and cuboid can be found by multiplying the dimensions. Complete the given table by finding the volume of the given objects.

Answer:

Question 2.
Complete the given table by finding the volume of the given objects.

Answer:

Question 3.
Find the number of bricks of dimension 20 cm × 5 cm × 10 cm required to construct a wall of dimension 300 cm × 200 cm × 20 cm.
Answer:

= 1200 bricks

Question 4.
How many sack of dimension 15 cm × 45 cm × 90 cm filled with rice can be kept in a room of dimension 3 m × 18 m × 9 m.
Answer:

Students can download 5th Maths Term 3 Chapter 3 Measurements Ex 3.1 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 3 Measurements Ex 3.1

Question 1.
Tick the object which has more volume

Answer:

Question 2.
Arrange the given objects according to their volume
(i)

Answer:

(ii)

Answer:

(i)

Answer: