## Samacheer Kalvi 6th Maths Guide Term 3 Chapter 1 Fractions Ex 1.1

Students can download Maths Chapter 1 Fractions Ex 1.1 Questions and Answers, Notes, Samacheer Kalvi 6th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

## Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 3 Chapter 1 Fractions Ex 1.1

Question 1.
Fill in the blanks:
(i) 7$$\frac{3}{4}$$ + 6$$\frac{1}{2}$$ ………..
(ii) The sum of a whole number and a proper fraction is called ……….
(iii) 5$$\frac{1}{3}$$ – 3$$\frac{1}{2}$$ ………..
(iv) 8 ÷ $$\frac{1}{2}$$ ………..
(v) The number which has its own reciprocal is ……….
Solution:

(ii) Mixed Fraction

(iii) 5$$\frac{1}{3}$$ – 3$$\frac{1}{2}$$
= $$\frac{16}{3}$$ – $$\frac{7}{2}$$ = $$\frac{32-21}{6}$$ = $$\frac{11}{6}$$
= 1$$\frac{5}{6}$$

(iv) 8 ÷ $$\frac{1}{2}$$
= 8 × $$\frac{2}{1}$$
= 16

(v) 1

The first step would be to write the mix number 223 as an improper fraction.

Question 2.
Say True or False
(i) 3$$\frac{1}{2}$$ can be written as 3 + $$\frac{1}{2}$$.
(ii) The sum of any two proper fractions is always an improper fraction.
(iii) The mixed fraction of $$\frac{13}{4}$$ is 3$$\frac{1}{4}$$.
(iv) The reciprocal of an improper fraction is always a proper fraction.
(v) 3$$\frac{1}{4}$$ × 3$$\frac{1}{4}$$ = 9$$\frac{1}{16}$$
Solution:
(i) True
(ii) False
(iii) True
(iv) True
(v) False

Question 3.
(i) Find the sum of $$\frac{1}{7}$$ and $$\frac{3}{9}$$.
(ii) What is the total of 3$$\frac{1}{3}$$ and 4$$\frac{1}{6}$$?
(iii) Simplify: 1$$\frac{3}{5}$$+5$$\frac{4}{7}$$.
(iv) Find the difference between $$\frac{8}{9}$$ and $$\frac{2}{7}$$
(v) Subtract: 1$$\frac{3}{5}$$ from 2$$\frac{1}{3}$$.
(vi) Simplify: 7$$\frac{2}{7}$$ – 3$$\frac{4}{21}$$
Solution:
(i) $$\frac{1}{7}$$ + $$\frac{3}{9}$$
= $$\frac{9+21}{63}$$ = $$\frac{30}{63}$$ = $$\frac{10}{21}$$

Question 4.
Convert mixed fractions into improper fractions and vice versa:
(i) 3$$\frac{7}{18}$$
(ii) $$\frac{99}{7}$$
(iii) $$\frac{47}{6}$$
(iv) 12$$\frac{1}{9}$$
Solution:
(i) 3$$\frac{7}{18}$$ = $$\frac{61}{18}$$
(ii) $$\frac{99}{7}$$ = 14$$\frac{1}{7}$$
(iii) $$\frac{47}{6}$$ = 7$$\frac{5}{6}$$
(iv) 12$$\frac{1}{9}$$ = $$\frac{109}{9}$$

Question 5.
Multiply the following:
(i) $$\frac{2}{3}$$ × 6
(ii) 8$$\frac{1}{3}$$ × 5
(iii) $$\frac{3}{8}$$ × $$\frac{4}{5}$$
(iv) 3$$\frac{5}{7}$$ × 1$$\frac{1}{13}$$
Solution:
(i) $$\frac{2}{3}$$ × 6 = 4

(ii) 8$$\frac{1}{3}$$ × 5
= $$\frac{25}{3}$$ × 5
= $$\frac{125}{3}$$
= 41$$\frac{2}{3}$$

(iii) $$\frac{3}{8}$$ × $$\frac{4}{5}$$
= $$\frac{12}{40}$$ = $$\frac{3}{10}$$

(iv) 3$$\frac{5}{7}$$ × 1$$\frac{1}{13}$$
= $$\frac{26}{7}$$ × $$\frac{14}{13}$$
= $$\frac{4}{1}$$
= 4

Question 6.
Divide the following
(i) $$\frac{3}{7}$$ ÷ 4
(ii) $$\frac{4}{3}$$ ÷ $$\frac{5}{9}$$
(iii) 4$$\frac{1}{5}$$ ÷ 3$$\frac{3}{4}$$
(iv) 9$$\frac{2}{3}$$ ÷ 1$$\frac{2}{3}$$
Solution:
(i) $$\frac{3}{7}$$ ÷ 4
= $$\frac{3}{7}$$ × $$\frac{1}{4}$$ = $$\frac{3}{28}$$

(ii) $$\frac{4}{3}$$ ÷ $$\frac{5}{9}$$
= $$\frac{4}{3}$$ × $$\frac{9}{5}$$
= $$\frac{12}{5}$$
= 2$$\frac{2}{5}$$

Question 7.
Gowri purchased 3$$\frac{1}{2}$$ kg of tomatoes, $$\frac{3}{4}$$ kg of brinjal and 1$$\frac{1}{4}$$ kg of onion. What is the total weight of the vegetables she bought?
Solution:
Total weight of vegetables bought

Question 8.
An oil tin contains 3$$\frac{3}{4}$$ litres of oil of which 2$$\frac{1}{2}$$ litres of oil is used. How much oil is left over?
Solution:

Question 9.
Nilavan can walk 4$$\frac{1}{2}$$ km in an hour. How much distance will he cover in 3$$\frac{1}{2}$$ hours?
Solution:
Distance walked in an hour = 4$$\frac{1}{2}$$ km
Distance covered in 3$$\frac{1}{2}$$
Hours

Question 10.
Ravi bought a curtain of length 15$$\frac{3}{4}$$ m. If he cut the curtain into small pieces each of length 2$$\frac{1}{4}$$ m, then how many small curtains will he get?
Solution:
Total length = 15$$\frac{3}{4}$$
Length of the small pieces = 2$$\frac{1}{4}$$
Small curtains obtained

= 7

Objective Type Questions

Question 11.
Which of the following statement is incorrect?
(a) $$\frac{1}{2}$$ > $$\frac{1}{3}$$
(b) $$\frac{7}{8}$$ > $$\frac{6}{7}$$
(c) $$\frac{8}{9}$$ < $$\frac{9}{10}$$
(d) $$\frac{10}{11}$$ > $$\frac{9}{10}$$
Solution:
(d) $$\frac{10}{11}$$ > $$\frac{9}{10}$$

Question 12.
The difference between $$\frac{3}{7}$$ and $$\frac{2}{9}$$ is
(a) $$\frac{13}{63}$$
(b) $$\frac{1}{9}$$
(c) $$\frac{1}{7}$$
(d) $$\frac{9}{16}$$
Solution:
(a) $$\frac{13}{63}$$

Question 13.
The reciprocal of $$\frac{53}{17}$$ is
(a) $$\frac{53}{17}$$
(b) 5$$\frac{3}{17}$$
(c) $$\frac{17}{53}$$
(d) 3$$\frac{5}{17}$$
Solution:
(c) $$\frac{17}{53}$$

Question 14.
If $$\frac{6}{7}=\frac{\mathbf{A}}{49}$$, then the value of A is
(a) 42
(b) 36
(c) 25
(d) 48
Solution:
(a) 42
Hint: $$\frac{6 \times 49}{7}=42$$

Question 15.
Pugazh has been given four choices for his pocket money by his father. Which of the choices should he take in order to get the maximum money?
(a) $$\frac{2}{3}$$ of Rs 150
(b) $$\frac{3}{5}$$ of Rs 150
(c) $$\frac{4}{5}$$ of Rs 150
(d) $$\frac{1}{5}$$ of Rs 150
Solution:
(c) $$\frac{4}{5}$$ of Rs 150

## Samacheer Kalvi 6th Social Science Guide Book Answers Solutions

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## Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Numbers Ex 1.4

Students can download Maths Chapter 1 Numbers Ex 1.4 Questions and Answers, Notes, Samacheer Kalvi 6th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

## Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 1 Numbers Ex 1.4

Question 1.
Fill in the blanks.
(i) The nearest 100 of 843 is _____
(ii) The nearest 1000 of 756 is ______
(iii) The nearest 10,000 of 85654 is ______
Solution:
(i) 800.
The digit in tens place is 4 < 5
(ii) 1000.
The digit in hundred places is 7 ≥ 5
(iii) 90,000.
The digit in a thousand places is 5 ≥ 5

Question 2.
Say True or False
(i) 8567 is rounded off as 8600 to the nearest 10.
(ii) 139 is rounded off as 100 to the nearest 100.
(iii) 1,70,51,972 is rounded off as 1,70,00,000 to the nearest lakh.
Solution:
(i) False
Hint: In one’s place the digit is 7 ≥ 5. So 8580
(ii) True
Hint: In tens place, we have 3 < 5. So 100
(iii) False
Hint: In ten thousand places the digit is 5 ≥ 5. So 1,71,000,000

Question 3.
Round off the following to the given nearest place.
(i) 4,065; hundred
(ii) 44,555; thousand
(iii) 86,943; ten thousand
(iv) 50,81,739; lakh
(v) 33,75,98,482; ten crore
Solution:
(i) 4100
(ii) 45,000
(iii) 90,000
(iv) 51,00,000
(v) 30,00,00,000

Question 4.
Estimate the sum of 157826 and 32469 rounded off to the nearest ten thousand.
Solution:
= 157826 + 32469
= 190295
When rounded off to nearest ten thousand = 1,90,000

Decimal numbers can be rounded to the nearest hundredth by observing the digit in the thousandths place.

Question 5.
Estimate by rounding off each number to the nearest hundred.
(i) 8074 + 4178
(ii) 1768977 + 130589
Solution:
(i) 8074 + 4178 = 12,252
When rounded off to nearest hundred 12,300

(ii) 1768977 + 130589 = 18,99,566
When rounded off to nearest hundred = 18,99,600

Question 6.
The population of a city was 43,43,645 in the year 2001 and 46,81,087 in the year 2011. Estimate the increase in population by rounding off to the nearest thousands.
Solution:
Population in 2001 = 43,43,645
Population in 2011 = 46,81,087
Increase in population = 46,81,087 – 43,43,645 = 3,37,442
When rounded off to the nearest thousand = 3,37,000

Objective Type Questions

Question 7.
The number which on rounding off to the nearest thousand gives 11000 is
(a) 10345
(b) 10855
(c) 11799
(d) 10056
Solution:
(b) 10855

Question 8.
The estimation to the nearest hundredth of 76812 is
(a) 77000
(b) 76000
(c) 76800
(d) 76900
Solution:
(c) 76800
In tens place the digit is 1 < 5, So 76800

Question 9.
The number 9785764 is rounded off to the nearest lakh as
(a) 9800000
(b) 9786000
(c) 9795600
(d) 9795000
Solution:
(a) 9800000

Question 10.
The estimated difference of 167826 and 2765 rounded off to the nearest thousand is
(a) 180000
(b) 165000
(c) 140000
(d) 155000
Solution:
(b) 165000

## Samacheer Kalvi 6th Maths Guide Term 2 Chapter 1 Numbers Ex 1.2

Students can download Maths Chapter 1 Numbers Ex 1.2 Questions and Answers, Notes, Samacheer Kalvi 6th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

## Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 2 Chapter 1 Numbers Ex 1.2

Question 1.
Fill in the blanks
(i) The HCF of 45 and 75 is …….
(ii) The HCF of two successive even numbers is …….
(iii) If the LCM of 3 and 9 is 9, then their HCF is ………
(iv) The LCM of 26, 39 and 52 is ……..
(v) The least number that should be added to 57 so that the sum is exactly divisible by 2, 3, 4 and 5 is ………
Solution:
(i) 15
(ii) 2
(iii) 3
(iv) 156
(v) 3

The Least common multiple (LCM) of 15 and 20 is 60.

Question 2.
Say True or False
(i) The numbers 57 and 69 are co-primes.
(ii) The HCF of 17 and 18 is 1.
(iii) The LCM of two successive numbers is the product of the numbers.
(iv) The LCM of two co-primes is the sum of the numbers.
(v) The HCF of two numbers is always a factor of their LCM.
Solution:
(i) False
(ii) True
(iii) True
(iv) False
(v) True

So, now the prime factorization of 84 with the upside-down division method is 2 × 2 × 3 × 7.

Question 3.
Find the HCF of each set of numbers using the prime factorisation method.
(i) 18, 24
(ii) 51, 85
(iii) 61, 76
(iv) 84, 120
(v) 27, 45, 81
(vi) 45, 55, 95
Solution:
(i) 18, 24

HCF = 2 × 3 = 6

(ii) 51, 85

HCF = 17

(iii) 61, 76
61 = 1 × 61
For 61, 76, the common factor is 1
HCF = 1

(iv) 84, 120

HCF = 2 × 2 × 3 = 12

(v) 27, 45, 81

HCF = 3 × 3 = 9

(vi) 45, 55, 95

Factors of 55 = 5 × 11
Factors of 45 = 3 × 3 × 5
Factors of 95 = 5 × 19
HCF = 5

Question 4.
Find the LCM of each set of numbers using the prime factorisation method.
(i) 6, 9
(ii) 8, 12
(iii) 10, 15
(iv) 14, 42
(v) 30, 40, 60
(vi) 15, 25, 75
Solution:
(i) 6, 9

Factors of 6 = 2 × 3
Factors of 9 = 3 × 3
LCM of 6 and 9 = 3 × 2 × 3 = 18

(ii) 8, 12

(iii) 10, 15

Factors of 10 = 2 × 5
Factors of 15 = 3 × 5
LCM of 10 and 15 = 5 × 2 × 3 = 30

(iv) 14, 42

Factors of 14 = 2 × 7
Factors of 42 = 2 × 3 × 7
LCM of 14 and 42 = 7 × 2 × 3 = 42

(v) 30, 40, 60

Factors of 30 = 2 × 3 × 5
Factors of 40 = 2 × 2 × 2 × 5
Factors of 60 = 2 × 2 × 3 × 5
LCM of 30, 40, 60 = 2 × 5 × 3 × 2 × 2 = 120

(vi) 15, 25, 75

Factors of 15 = 3 × 5
Factors of 25 =5 × 5
Factors of 75 = 3 × 5 × 5
LCM of 15, 25, 75 = 5 × 3 × 5 = 75

Question 5.
Find the HCF and the LCM of the numbers 154, 198, 286
Solution:
HCF

Factors of 154 = 2 × 7 × 11
Factors of 198 = 2 × 3 × 3 × 11
Factors of 286 = 2 × 13 × 11
HCF of 154, 198, 286 = 11 × 2 = 22
LCM

LCM = 2 × 11 × 7 × 9 × 13
= 22 × 63 × 13
= 18018

Question 6.
What is the greatest possible volume of a vessel that can be used to measure exactly the volume of milk in cans (in full capacity) of 80 litres, 100 litres and 120 litres?
Solution:
This is an HCF related problem. So, we need to find the HCF of 80, 100, 120

80 = 2 × 2 × 2 × 2 × 5
100 = 2 × 2 × 5 × 5
120 = 2 × 2 × 2 × 3 × 5
HCF of 80, 100 and 120 = 2 × 2 × 5 = 20
Volume of the vessel = 20 litres

Question 7.
The traffic lights at three different road junctions change after every 40 seconds, 60 seconds, and 72 seconds respectively. If they changed simultaneously together at 8 a.m at the junctions, at what time will they simultaneously change together again?
Solution:
This is an LCM related problem. So, we need to find the LCM of 40, 60, 72

LCM of 40, 60 and 72
= 2 × 2 × 3 × 5 × 2 × 1 × 1 × 3
= 360 seconds
= 6 minutes
The traffic lights will change simultane¬ously again at 8 : 06 am.

Question 8.
The LCM of two numbers is 210 and their HCF is 14. How many such pairs are possible.
Solution:
Product of two numbers = LCM × HCF
x × y = 210 × 14
x × y = 2940
(12, 245), (20, 147)
Two pairs are possible.

Question 9.
The LCM of two numbers is 6 times their HCF. If the HCF is 12 and one of the numbers is 36, then find the other number.
Solution:
36x = 6 × 12 × 12
⇒ $$x=\frac{6 \times 12 \times 12}{36}=24$$

Objective Type Questions

Question 10.
Which of the following pairs is co-prime?
(a) 51, 63
(b) 52, 91
(c) 71, 81
(d) 81, 99
Solution:
(c) 71, 81

Question 11.
The greatest four-digit number which is exactly divisible by 8, 9, and 12 is
(a) 9999
(b) 9996
(c) 9696
(d) 9936
Solution:
(d) 9936

Question 12.
The HCF of two numbers is 2 and their LCM is 154. If the difference between the numbers is 8, then the sum is
(a) 26
(b) 36
(c) 46
(d) 56
Solution:
(b) 36

Question 13.
Which of the following cannot be the HCF of two numbers whose LCM is 120?
(a) 60
(b) 40
(c) 80
(d) 30
Solution:
(c) 80

## Samacheer Kalvi 6th Maths Guide Term 1 Chapter 3 Ratio and Proportion Ex 3.2

Students can download Maths Chapter 3 Ratio and Proportion Ex 3.2 Questions and Answers, Notes, Samacheer Kalvi 6th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

## Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 3 Ratio and Proportion Ex 3.2

Question 1.
Fill in the blanks of the given equivalent ratios.
(i) 3 : 5 = 9 : ……
(ii) 4 : 5 = …… : 10
(iii) 6 : …… = 1 : 2
Solution:
(i) 15
Hint: $$\frac{3}{5}=\frac{3 \times 3}{5 \times 3}=\frac{9}{15}$$
(ii) 8
Hint: $$\frac{4}{5}=\frac{4 \times 2}{5 \times 2}=\frac{8}{10}$$
(iii) 12
Hint: $$\frac{1}{2}=\frac{1 \times 6}{2 \times 6}=\frac{6}{12}$$

Question 2.
Complete the table.

Solution:
(i) 1 feet = 12 inches
3 feet = 3 × 12 inches = 36 inches
72 inches = 6 × 12 inches = 6 feet

(ii) 1 week = 7 days
2 weeks = 2 × 7 days = 14 days
63 days = 9 × 7 days = 9 weeks

Question 3.
Say True or False.
(i) 5 : 7 is equivalent to 21 : 15
(ii) If 40 is divided in the ratio 3 : 2, then the larger part is 24
Solution:
(i) False
Hint: $$\frac{21}{15}=\frac{7}{5}=7: 5$$
(ii) True
Hint: $$\frac{3}{5} \times 40=24$$

Handy LCM of two or more numbers Calculator displays LCM of 365, 838, 862 in a fraction of seconds i.e.

Question 4.
Give two equivalent ratios for each of the following.
(i) 3 : 2
(ii) 1 : 6
(iii) 5 : 4
Solution:
(i) 3 : 2

3 : 2 = 6 : 4 = 9 : 6

(ii) 1 : 6

1 : 6 = 2 : 12 = 3 : 18

(iii) 5 : 4

5 : 4 = 10 : 8 = 15 : 12

Question 5.
Which of the two ratios is larger?
(i) 4 : 5 or 8 : 15
(ii) 3 : 4 or 7 : 8
(iii) 1 : 2 or 2 : 1
Solution:
(i) 4 : 5 (or) 8 : 15

4 : 5 > 8 : 15

(ii) 3 : 4 (or) 7 : 8

7 : 8 > 3 : 4

(iii) 1 : 2 (or) 2 : 1
1 : 2 = $$\frac{1}{2}$$
2 : 1 = $$\frac{2}{1}$$
= 2
$$\frac{2}{1}$$ > $$\frac{1}{2}$$
2 : 1 > 1 : 2

Question 6.
Divide the numbers given below in the required ratio.
(i) 20 in the ratio 3 : 2
(ii) 27 in the ratio 4 : 5
(iii) 40 in the ratio 6 : 14.
Solution:
(i) Ratio = 3 : 2
Sum of the ratio = 3 + 2 = 5
5 parts = 20
1 part = $$\frac{20}{5}$$ = 4
3 parts = 3 × 4 = 12
2 parts = 2 × 4 = 8
20 can be divided in the form as 12, 8.

(ii) Ratio = 4 : 5
Sum of the ratio = 4 + 5 = 9
9 parts = 27
1 part = $$\frac{27}{9}$$ = 3
4 parts = 4 × 3 = 12
5 parts = 5 × 3 =15
27 can be divided in the form as 12, 15.

(iii) 40 in the ratio 6 : 14
Ratio = 6 : 14
Sum of the ratio = 6 + 14 = 20
20 parts = 40
1 part = $$\frac{40}{20}$$ = 2
6 parts = 2 × 6 = 12
14 parts = 2 × 14 = 28
40 can be divided in the form as 12, 28.

Question 7.
In a family, the amount spent in a month for buying Provisions and Vegetables are in the ratio 3 : 2. If the allotted amount is Rs 4000, then what will be the amount spent for
(i) Provisions and
(ii) Vegetables?
Solution:
Allotted amount = Rs 4000
Ratio = 3 : 2
Sum of the ratio = 3 + 2 = 5
5 parts = Rs 4000
1 part = Rs $$\frac{4000}{5}$$ = Rs 800
Provisions : Vegetables = 3 : 2
3 parts = 3 × Rs 800 = Rs 2400
2 parts = 2 × Rs 800 = Rs 1600
Amount spent for provisions = Rs 2400
Amount spent for vegetables = Rs 1600

Question 8.
A line segment 63 cm long is to be divided into two parts in the ratio 3 : 4. Find the length of each part.
Solution:
Total length = 63 cm Ratio = 3 : 4
Sum of the ratio = 3 + 4 = 7
7 parts = 63 cm
1 part = $$\frac{63}{7}$$ = 9 cm
3 parts = 3 × 9 cm = 27 cm
4 parts = 4 × 9 cm = 36 cm
∴ 63 cm can be divided into the parts as 27 cm and 36 cm.

Objective Type Questions

Question 9.
If 2 : 3 and 4 : …… are equivalent ratios, then the missing term is
(a) 6
(b) 2
(c) 4
(d) 3
Solution:
(a) 6

Question 10.
An equivalent ratio of 4 : 7 is
(a) 1 : 3
(b) 8 : 15
(c) 14 : 8
(d) 12 : 21
Solution:
(d) 12 : 21

Question 11.
Which is not an equivalent ratio of $$\frac{16}{24}$$?
(a) $$\frac{6}{9}$$
(b) $$\frac{12}{18}$$
(c) $$\frac{10}{15}$$
(d) $$\frac{20}{28}$$
Solution:
(d) $$\frac{20}{28}$$

Question 12.
If Rs 1600 is divided
(a) Rs 480
(b) Rs 800
(c) Rs 1000
(d) Rs 200
Solution:
(c) Rs 1000

## Samacheer Kalvi 6th Science Guide Term 1 Chapter 4 The Living World of Plants

Students can download 6th Science Term 1 Chapter 4 The Living World of Plants Questions and Answers, Notes, Samacheer Kalvi 6th Science Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

## Tamilnadu Samacheer Kalvi 6th Science Solutions Term 1 Chapter 4 The Living World of Plants

### Samacheer Kalvi 6th Science The Living World of Plants Text Book Back Questions and Answers

Question 1.
The pond is an example of ………
(a) Marine habitat
(b) Freshwater habitat
(c) Deserts
(d) Mountain
(b) Freshwater habitat

Question 2.
The important function of stomata is ______
(a) Conduction
(b) Transpiration
(c) Photosynthesis
(d) Absorption
(b) Transpiration

Question 3.
Organs of absorption are ………
(a) Root
(b) Stem
(c) Leaf
(d) Flower
(a) Root

Question 4.
The habitat of water hyacinth is ______
(a) Aquatic
(b) Terrestrial
(c) Desert
(d) Mountain
(a) Aquatic

II. True or False – If false give the correct answer.

1. Plants can live without water.
2. All plants have chlorophyll.
3. Plants have three parts; the root, the stem, and the leaves.
4. Mountain is an example of a freshwater habitat.
5. Root is modified into spines.
6. Green plants need sunlight.

1. False – They need water to carry out various functions.
2. False – Only green plants have chlorophyll.
3. True
4. False – Mountain is an example of Terrestrial habitat.
5. False – Spines are usually modifications of leaves.
6. True

III. Fill in the blanks.

1. Earth’s surface is covered by ……….. % of water.
2. The driest places on earth are ……….
3. Fixation and absorption are the main functions of ……….
4. Primary organs of photosynthesis are ………..
5. Taproot system present in ……….. plants.

1. 70%
2. Deserts
3. roots
4. leave
5. dicot.

IV. Match the following:

(i) – d
(ii) – c
(iii) – b
(iv) – e
(v) – a

V. Arrange in the correct sequence.

Question 1.
Leaf – Stem – Root – Flower
root – stem – leaf – flower

Question 2.
Transpiration – Conduction – Absorption – Fixation.
Fixation, Absorption, Conduction, Transpiration.

Question 1.
Classify plants on the basis of their habitat.
Terrestrial and Aquatic are the 2 habitats

Question 2.
Identify the desert plant from the following – Cactus, Hydrilla, Mango, and Rose.
Cactus plants – grow in deserts, and are able to store water in their stem.

Question 3.
Define the term habitat.
Each and every organism needs a place to live and reproduce known as habitat.
The dwelling place of any organism is its habitat. Eg. Aquatic habitat

Question 4.
Relate the terms leaves and photosynthesis.
Leaves are green in colour, they have chlorophyll and do photosynthesis.

Question 1.
Why do you call Jasmine plants a twiner?
Weak plant, cannot stand on its own, must climb on any support to survive.

Question 2.
Compare the taproot and fibrous root systems.
Taproot system:

1. Consists of a single root.
2. it grows straight down in the ground
3. Seen in misogynous plants.

Fibrous root system:

1. Consists cluster of roots.
2. It is thin and uniform in size.
3. Seen in monocotyledonous plants.

Question 3.
Distinguish between terrestrial and aquatic habitats.

Question 4.
List out the plants present in your school garden.
Mango tree, Neem tree, Water lily, Clitoria, Hibiscus

Question 1.
Make a list of functions of root & stem.
Functions of root:
The root,

• Fixes the plant to the soil.
• Absorbs water and minerals from the soil.
• Stores food in some plants like carrots and beetroot.

Functions of stem:
The stem,

• Supports the branches, leaves, flowers, and fruits.
• Transports water and minerals from roots to upper aerial plant parts.
• Transports the prepared food from leaves to other parts.
• Stores food as in the case of sugarcane.

Question 2.
Study the given concept map. Connect them correcting by drawing arrow marks. Complete the map by filling in the blanks.

Class 6 Science MCQ with Answers ·

### Samacheer Kalvi 6th Science The Living World of Plants Additional Important Questions and Answers

I. Multiple Choice Questions.

Question 1.
Maize has ……….
(a) taproot
(b) fibrous root
(d) Fasciculate root
(b) fibrous root

Question 2.
The underground part of the main axis of a plant is known as ______
(a) shoot
(b) node
(c) root
(d) leaf
(c) root

Question 3.
The stalk of the leaf is known
(a) peduncle
(b) rachis
(c) pedicel
d) petiole
(d) petiole

Question 4.
On the lower side of the leaf, there are tiny pores or openings known as ______
(a) Leaf base
(b) midrib
(c) petiole
(d) stomata
(d) stomata

Question 5.
The diameter of the leaf of Victoria amazonica is
(a) 2 meters
(b) 2.5 cm
(c) 3 meters
(d) 1 meter
(c) 3 meters

II. Fill in the blanks.

1. Special features in plants which help them to survive in the habitats they live are known as ……….
2. The Great Indian Desert is an arid region of rolling sandhills on the Indian sub continent is known as ……….
3. ………. is the main vein of the lamina of the leaf.
4. A change in an organism caused by environmental factors is known as ………

2. Thar desert
3. Midrib
4. Modification

III. Arrange in the correct sequence.

Question 1.
Sea – Lake – River – Pond
Pond – Lake – River – Pond.

Question 2.
Internode – Node – Axillary Bud – Terminal Bud
Terminal Bud – Axillary Bud – Node – Internodes.

Question 1.
Draw the structure of a leaf and neatly label the parts.

Question 2.
List the main part of a flowering plant.
The flowering plant consists of two main parts. They are

1. Root system
2. Shoot system

Question 3.
Differentiate between Gymnosperm and Angiosperm.
Both groups produces seeds.
Gymnosperms – Non flowering but produce naked seeds Eg. Pinus, Cycas.
Angiosperms – Flowering and produce closed seeds Eg. Mango – Rose

Question 4.
Give some examples of monocotyledonous plants and dicotyledonous plants.
Monocotyledonous plant – Grass, Paddy, Maize
Dicotyledonous plant – Bean, Mango, Neem

Question 5.
Notes on Thorns or Spines.
Some plants leave – modified into sharp structures known as Thorns or Spines help to reduce water loss.
Eg – Agave – (leaf apex & margin modified into spines).

Question 1.
Explain Tendril climber.
Tendril a twining climbing organ of some weak stemmed plants.
It coils around support and helps the plant to climb.

1. Sweet peas – Here leaflets are modified into tendrils.
2. Bitter gourd – Axillary buds of plant-modified into tendril, help climb up.

Question 2.

1. Dry places on earth
2. Less rainfall – less than 25 cm annually.
3. Deserts cover 20% of the earth’s surface.
4. Plants – Adapted to withstand severe heat.

Thick leaves help them to store water and minerals. Eg. Aloe

1. Stems modified to store water. Eg. Cactus
2. Leaves – modified into spines – Opuntia.

Question 3.
Study was given concept map. Connect them by drawing marks- for example, the map by filling the blanks.

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## Samacheer Kalvi 6th English Guide Term 2 Supplementary Chapter 2 Gulliver’s Travel

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### 6th English Guide Gulliver’s Travel Text Book Back Questions and Answers

Textual Exercises (Text Book Page No. 134)

Read and Understand (Text Book Page No. 134)

A. Read the following statements. Say True or False.

1. Gulliver was the captain of the ship.
False

2. One of the Lilliputians gave a ten minutes talk in Gulliver’s language.
False

3. Gulliver took the small creatures in his hand and crushed them.
False

4. The horses were four and a half inches tall.
True

5. The war between the two kingdoms ended in peace.
True

B. Identify the speaker/character.

1. He felt something moving along his body almost up to his chin.
Gulliver

2. They somehow managed to put him on the platform.
The Lilliputians

3. “Don’t let us down now, Gulliver; we need your help”.
The Emperor

C. Choose the right answer. (Text Book Page No. 135)

1. Gulliver managed to reach the land as he was
a) A doctor
b) One of the crews
c) a swimmer
d) the captain
c) a swimmer

2. Gulliver was set free because the emperor
a) was afraid of him
b) confirmed that he was not harmful.
c) was a kind hearted person.
d) wanted to get something from him.
b) confirmed that he was not harmful

3. Gulliver was hailed as a hero because he
a) made the army of Blefuscu giddy
b) fought with the army of Blefuscu.
c) drowned the army of Blefuscu in the water.
d) defeated the emperor of Blefuscu.
d) defeated the emperor of Blefuscu

D. Discuss in groups. Retell the story in your own words. Each one should say one sentence.

You can begin like this:
Gulliver was travelling in a ship. One stormy night, the ship was wrecked ………

Gulliver was travelling in a ship. One stormy night, the ship was wrecked. Gulliver was a good swimmer. So, he reached the land by swimming. The land appeared strange and lonely. He saw no human beings, he was hungry and tired. He fell on a patch of grass and slept. When he woke up he found his hands and legs tied down. There were a number of creatures not more than six inches high. He later learned they were Lilliputians. He was taken to the Emperor. He received Gulliver. He set him free with a condition that he would do no harm to them. Once, the neighbouring kingdom, declared war on Lilliput. The Emperor needed Gulliver’s help.

Gulliver walked into a sea and tied with a long rope all the ships of the enemy together he pulled the ships going round and round the whole day. They were not in a position to fight. So, the enemy king begged for peace between the two countries. Gulliver was hailed as a hero.

1. How did Gulliver overcome the adversity?
Gulliver’s ship was wrecked. He reached a land where the Lilliputians lived. They were not more than six inches high. Gulliver was taken to the emperor with his hands and legs tied. The emperor received him. Gulliver was given food and drink. He was lodged in an old and amused temple. Gulliver overcame his adversity by helping the Emperor and his people in many ways. Once the neighbouring kingdom declared war on Lilliput. It was Gulliver who defeated the enemy king made peace with the Emperor. Thus Gulliver overcame his adversity by being kind, helping, and wise.

2. How should one react to adversity?
When Gulliver faced adversity he remained patient. He was kind to all the Lilliputians and the Emperor. Once the neighbouring country declared war on Lilliput. Then it was Gulliver who saved Lilliput and earned the respect and love of the Emperor and the people.

3. Describe Gulliver’s encounter with the army of Blefuscu?
The king of Blefuscu once declared war on Lilliput. The Emperor needed help from Gulliver. Gulliver walked into the sea and tied with a long rope all the hundred ships of the enemy together. He dragged them in the water and pulled the ships, the whole day going round and round. The army of Blefuscu was giddy and was not in a position to fight. The king surrendered to the Emperor and made peace with him. It was Gulliver who brought victory to the Emperor.

Project

F. Look at the traffic signals and write down the traffic rule against each signal.

Connecting to Self

G. Look at these pictures. Think of how you must behave when you visit these places. Discuss with your partner and complete the table.

 Use dust bins Do not throw rubbish in public places Put waste into dustbins Don’t throw down uneaten food. Use toilet Don’t spit on the road. Keep the coast clean Don’t pass urine on the way. Keep the environment clear Don’t walk the meadow. Dust-free Don’t pluck flowers.

Step to Success

e.g. 1. Leaves 2. Fruit 3. Seed 4. Flowers 5. Root
a) 2,4,5,1,3
b) 3,5,1,4,2
c) 1,2,3,4,5
d) 5,3,1,2,4
b) 3, 5,1, 4, 2

1. 1. Drive 2. Get in 3. Arrive 4. Park 5. Open door
a) 2,1,3,5,4
b) 5,2,1,3,4
c) 3,4,5,1,2
d) 3,5,1,2,4
b) 5, 2,1,3, 4

2. 1. Travel 2. Book 3. Plan 4. Confirm 5. Enjoy
a) 3,2,4,1,5
b) 4,5,3,2,1
c) 1,2,3,4,5
d) 5,4,2,3,1
a) 3, 2, 4,1, 5

3. 1. Rest 2. Return 3. Supper 4. Go out 5. Visit
a) 1,2,3,4,5
b) 4,5,1,2,3
c) 4,5,2,3,1
d) 5,4,3,2,1
c) 4, 5, 2,3,1

4. 1. Check out 2. Pack 3. Pay bill 4. Vacate 5. Drive
a) 3,4,5,2,1
b) 1,2,3,4,5
c) 5,4,3,2,1
d) 2,4,3,1,5
d) 2, 4, 3,1, 5

5. 1. Wait 2. Slow 3. Go 4. Stop 5. Get ready
a) 2,4,1,5,3
b) 1,2,3,4,5
c) 5,4,3,2,1
d) 3,4,2,1,5
a) 2,4,1, 5,3

### Gulliver’s Travel Summary in English

While Gulliver was going, on a long voyage, his ship sank in a violent storm. However, he managed to escape and reached the island by nearing. He was hungry and exhausted so he fell to a patch of grass. When he woke he was tied down by dwarf (six inches) people who called themselves Lilliputians. He was taken to the capital of the Island. The Emperor received him. He was set free on condition. He was happy there. The neighbouring king of Blefuscu declared war on Lilliput. The Emperor needed Gulliver’s help. Gulliver pulled the all shipping the whole day. The king of Blefuicu begged for peace. The Emperor agreed. Gulliver was hailed as a hero by Lilliputians.

### Gulliver’s Travel Summary in Tamil

கலிபா நீண்ட பயணத்தில் செல்லும்போது, அவரது கப்பல் கடுமையான புயலில் மூழ்கியது. இருப்பினும், அவர் தப்பித்து அருகிலுள்ள தீவை அடைந்தார். அவர் பசியில் களைப்பும் அடைந்ததார். அதனால், அவர் புல்லின் மீது விழுந்தார். அவர் எழுந்தபோது லில்லிபுத்தியர்கள் என்று அழைத்த குள்ளர்கள் (ஆறு அங்குல) மக்களால் அவர் கட்டப்ட்டார். அவர் தீவின் தலைநகருக்கு கொண்டு செல்லப்ட்டார். சக்கரவர்த்தி அவரை வரவேற்றார். அவர் அங்கு மகிழ்ச்சியாக இருந்தார். பக்கத்து மன்னர் பிலிபியூஸ்க்கு லில்லிபுட்டின்மீது போரை அறிவித்தார். மன்னர் கலிபரின் உதவியை வேண்டினார். கலிபர் அனைத்து கப்பல்களையும் கட்டி நாள்முழுவதும் இழுத்தார். பிலியூயூஸ்க்கு அரசன் சமாதானத்தை கெஞ்சிக் கேட்டார். ஒப்புக்கொண்டார். கலிபர் தலைவர் என புகழப்பட்டார்.

## Samacheer Kalvi 6th English Guide Term 2 Supplementary Chapter 1 Think to Win

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### 6th English Guide Think to Win Text Book Back Questions and Answers

Textual Exercises (Text Book Page No. 105)

1. “Girls you are a good team.”
Which team do the girls belong to?
b) Hockey
c) Relay
d) Volleyball
c) Relay

2. Springfields is the name of a …………………….. .
a) team
b) house
c) company
d) school
d) school

3. The inter-school sports meet refers to competitions among the …………………….. .
a) teams of the same school
b) schools in the locality
c) schools in neighborhood
d) schools from other districts
b) schools in the locality

4. Seema is Rucha’s …………………….. .
a) friend
b) teammate
c) younger sister
d) opponent
c) younger sister

5. Order the names of the members in Team B relay event. Shabnam was followed by
a) Neelam, Aruna, Rucha
b) Arana, Rucha, Neelam
c) Neelam, Rucha, Arana
d) Arana, Neelam, Rucha
a) Neelam, Aruna, Rucha

1. How does Rucha differ from her sister?
Rucha is overprotective of herself. She never did things rashly. Even in running ‘ and playing, she would be conscious of her movements. But Seema, her younger sister was bold and was ready to take any risks.

2. ‘Springfields has a runner and they call her P.T. Usha.’ Why did they call her so?
The runner of Springfields ran as fast as RT. Usha. So she was called P. T. Usha.

3. Describe the qualities of the new P.T. Instructor Mr. Prakash.
The new P.T. Instructor was very enthusiastic about sports and drove the children hard – praising them, scolding and correcting them. But most of the time, he encourages and advises them a lot.

4. What words were ringing in Rucha’s ears when she was running in the relay?
The words “Think to win” were running in ‘Rucha’s ears when she was running in the relay.

5. What did Rucha finally realise about herself?
She realized that she had overcome her hesitations and denials. She could win, whenever she chose to do so.

C. Read the given lines and answer the questions : (Text Book Page No. 106)

1. His voice came from some distance away and,
Rucha realized that he was not holding the bicycle anymore.
“I will fall / will fall” she wailed.
a) What was she afraid of?
She was afraid of falling off the bicycle.

b) Was the boy closely following her?
No, the boy was not closely following her.

2. For the past two weeks he had been teaching her to ride.
a) Who was teaching whom? ‘
Vishnu was teaching Rucha to ride the bicycle.

b) What was he teaching?
He was teaching me how to ride a bicycle.

3. Even ‘P. T. Usha’came to shake her hand.
“I thought I was fast, but you were simply superb!”
she shook hands with her.
a) Who does the word ‘you’ refer to?
The word ‘you’ refers to Rucha.

b) What quality of the speaker is revealed?
The true spirit of a sportsperson is revealed here

Imagine you are Rucha and make a diary entry on your feelings about the day’s happenings and your victory. The start is given. Complete the diary.

E. Discuss in class

How did Rucha overcome her self-doubts? How can shyness and fear be overcome?
Rucha overcame her self-doubts. She was always thinking of Prakash Sir’s words “Think to A win’. Then he said that he wanted her to have a positive attitude. These words of Prakash sir made Rucha overcome her self-doubts.

We can overcome shyness and fear only by forgetting ourselves while playing the game.

Step to Success (Text Book Page No. 108)

Identify the sport name from the given wuzzles. One is done for you.

Find the odd one out:

eg. Weight lifting, Boxing, Silambam, Fencing
Weight lifting

1. Hide and Seek, Kho-Kho, Tennikoit, Kabaddi
Tennikoit

Cycling

3. Trapeze, Throw Ball, Bowling, Goalball
Trapeze

4. Snooker, Polo, Five Pins, Carrom Board
Polo

5. Cricket, Base Ball, Hockey, Basket Ball
Base Ball

### Think to Win Summary in English

Rucha was a ten years old girl, she learned to ride a bicycle. When she was riding the bicycle, she was wobbled and fell down. Even in running and playing, she would be conscious of her movements. Inter-house badminton matches will start in her school next week. Rucha was on the senior team. She lost the game by just two points. She became gloomy and despair. She would train with the rest of them for relay matches under the new PT instructor, Prakash Sir. The new P.T instructor Prakash Sir encouraged her during the relay match by saying that only ‘Think to Win’. At last, She won the relay match.

### Think to Win Summary in Tamil

ருச்சா ஒரு பத்துவயது பெண். அவள் சைக்கிள் ஓட்டக் கற்றுக்கொண்டாள். அவள் சைக்கிள் ஓட்டும்போது அவள் தள்ளாடி கீழே விழுந்தாள். ஓடுவதிலும் விளையாடுவதிலும் கூட அவள் எச்சரிக்கை விழிப்புணர்வுடன் இருப்பாள். இண்டர்ஹவுஸ் பூப்பந்து போட்டிகள் அவரது பள்ளியில் அடுத்த வாரத்தில் தொடங்கும். ருச்சா இளையோர் அணியில் இருந்தாள். அவன் இரண்டு புள்ளிகளால் ஆட்டத்தை இழந்தாள். அதனால் அவள் விரக்தியடைந்தாள். பிரகாஷ் ஐயா என்ற புதிய பயிற்சியாளரின் அறிவுறுத்தலின் கீழ் தொடர் ஓட்டப்போட்டிக்காக அவள் மற்றவர்களுடன் பயிற்சி பெறுவாள். புதிய பயிற்சியாளர் பிரகாஷ் சார் வெற்றி பெற யோசி மட்டுமே என்று ருச்சாவை தொடர் ஓட்டப் போட்தொடர் ஓட்டப்போட்டியின் போது அவளுக்கு அறிவுரை கூறி ஊக்குவித்தார். கடைசியாக அவள் தொடர் ஓட்டப் போட்டியில் வென்றாள்.

### Think to Win About the Author in English

The author of this entry Mrs.Lata Bilaney Kaku, known as Lata Kaku’ is one of the famous freelance writers in India. She was bom in 1969 and completed her schooling in Presentation Convent, Delhi. She has attained the Honours degree for Zoology at the University of Delhi.

Think to Win About the Author in Tamil

லதா காக்கு என அறியப்படுகிற இந்தக் கதையின் ஆசிரியரான லதா பிலானி காக்கு இந்தியாவின் பத்திரிக்கை சாராத புகழ்பெற்ற பொது எழுத்தாளர்களில் ஒருவர் ஆவார். 1969இல் பிறந்த இவர், டெல்லியில் உள்ள ப்ரசண்டேஷன் கான்வென்ட்டில் தன்னுடைய பள்ளிப்படிபை முடித்தார். டெல்லி பல்கலைக் கழகத்தில் விலங்கியல் துறையில் இவர் கௌரவப் பட்டம் பெற்றுள்ளார்.