Students can download 5th Maths Term 3 Chapter 4 Algebra Ex 4.2 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 4 Algebra Ex 4.2

Question 1.
Say whether true or false

(i) (23 + 4) = (4 + 23)
Hint: 27 = 27
Answer:
True

(ii) (9 + 4) > 12
Hint: 13 > 12
Answer:
True

Samacheer Kalvi 5th Maths Guide Term 3 Chapter 4 Algebra Ex 4.2

(iii) (9 + 4) < 12
Hint: 13 < 12
Answer:
False

(iv) 11 > 121
Answer:
False

(v) 142 < 142
Answer:
False

(vi) 112 = 112
Answer:
True

Samacheer Kalvi 5th Maths Guide Term 3 Chapter 4 Algebra Ex 4.2

(vii) (6 × 5) (32 – 2)
Hint: 30 = 30
Answer:
True

(viii) \(\frac { 49 }{ 7 }\) > 7
Hint: \(\frac { 49 }{ 7 }\) = 7
Answer:
False

(ix) (4 × 3) = (3 × 4)
Hint: 4 × 3 = 12 ;
3 × 4 = 12
Answer:
True

Samacheer Kalvi 5th Maths Guide Term 3 Chapter 4 Algebra Ex 4.2

(x) (21 + 0) = 21
Answer:
True

Question 2.
Fill in the blanks with the right symbol (<, > or =).
(i) (54 ÷ 9) ___ (8 – 3)
Answer:
54 ÷ 9 = 6
8 – 3 = 5
6 > 5
(54 ÷ 9) > 8 – 3

(ii)(6 + 2) ___ (4 × 2)
Answer:
6 + 2 = 8
4 × 2 = 8
8 = 8
(6 + 2) = (4 × 2)

Samacheer Kalvi 5th Maths Guide Term 3 Chapter 4 Algebra Ex 4.2

(iii) (10 × 2) ____ (15 + 20)
Answer:
10 × 2 = 20
15 + 20 = 35
20 < 35
10 × 2 < 15 + 20

Question 3.
Fill in the blanks in the expressions with the suitable number.
(i) (1 × 9) = (___ × 1)
Answer:
(1 × 9) = (9 × 1)

(ii) (6 × 3) > (8 × ___)
Answer:
6 × 3 = 18
8 × 2 = 16
18 > 16
6 × 3 > (8 × 2)

Samacheer Kalvi 5th Maths Guide Term 3 Chapter 4 Algebra Ex 4.2

(iii) (36 ÷ 6) < (___ × 7)
Answer:
36 ÷ 6 = 6
1 × 7 = 7
6 < 7
(36 ÷ 6) < 1 × 7

(iv) (0 + 2) > (7 × ____)
Answer:
(0 + 2) = 2
7 × 0 = 0
2 > 0
(0 + 2) > (7 × 0)

(v) (42 ÷ 7) = (4 + ____)
Answer:
(42 ÷ 7) = 6
4 + 2 = 6
(42 ÷ 7) = (4 + 2)

Samacheer Kalvi 5th Maths Guide Term 3 Chapter 4 Algebra Ex 4.2

(vi) (6 – ___) < (1 + 2)
Answer:
6 – 4 = 2
1 + 2 = 3
2 < 3
(6 – 3) < (1 + 2)

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