Students can download Maths Chapter 1 Numbers Ex 1.5 Questions and Answers, Notes, Samacheer Kalvi 6th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

Tamilnadu Samacheer Kalvi 6th Maths Solutions Term 1 Chapter 1 Numbers Ex 1.5

Question 1.
Fill in the blanks.
(i) The difference between the smallest natural number and the smallest whole number is ……….
(ii) 17 × …….. = 34 × 17
(iii) When ……… is added to a number, it remains the same.
(iv) Division by ………. is not defined.
(v) Multiplication by ……… leaves a number unchanged.
Solution:
(i) 1
(ii) 34
(iii) Zero
(iv) 0
(v) 1

 Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

Question 2.
Say True or False.

  1. 0 is the identity for multiplication of whole numbers.
  2. The Sum of two whole numbers is always less than their product.
  3. Both addition and multiplication are associative for whole numbers.
  4. Both addition and multiplication are commutative for whole numbers.
  5. Multiplication is distributive over addition for whole numbers.

Solution:

  1. False
  2. False
  3. True
  4. True
  5. True

 Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

Question 3.
Name the property being illustrated in each of the cases given below.

  1. 75 + 34 = 34 + 75
  2. (12 × 4) × 8 = 12 × (4 × 8)
  3. 50 + 0 = 50
  4. 50 × 1 = 50
  5. 50 × 42 = 50 × 40 + 50 × 2

Solution:

  1. Commutativity for addition
  2. Associativity for multiplication
  3. Zero is the additive identity
  4. One is the multiplicative identity
  5. Distributivity of multiplication over addition

 Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

Question 4.
Use the properties of whole numbers and simplify.
(i) 50 × 102
(ii) 500 × 689 – 500 × 89
(iii) 4 × 132 × 25
(iv) 196 + 34 + 104
Solution:
(i) 50 × 102
= 50 × (100 + 2)
= (50 × 100) + (50 × 2)
= 5000 + 100 = 5100

(ii) 500 × 689 – 500 × 89
= 500 × (689 – 89)
= 344500 – 44500
= 300000
= 500 × (689 – 89)
= 500 × 600
= 3,00000

(iii) (4 × 132) × 25
= 4 × (132 × 25)
= (4 × 132) × 25
= 528 × 25
= 13200
= 4 × (132 × 25)
= 4 × 3300
= 13200

(iv) (196 + 34) + 104 = 196 + (34 + 104)
(196 + 34) + 104 = 230 + 104 = 334
196 + (34 + 104) = 196 + 138 = 334

 Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

Objective Type Questions

Question 5.
(53 + 49) × 0 is
(a) 102
(b) 0
(c) 1
(d) 53 + 49 × 0
Solution:
(b) 0

Question 6.
\(\frac{59}{1}\) is
(a) 1
(b) 0
(c) \(\frac{1}{59}\)
(d) 59
Solution:
(d) 59

 Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

Question 7.
The product of a non-zero whole number and its successor is always
(a) an even number
(b) an odd number
(c) zero
(d) none of these
Solution:
(a) an even number

Question 8.
The whole number that does not have a predecessor is
(a) 10
(b) 0
(c) 1
(d) none of these
Solution:
(b) 0

 Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

Question 9.
Which of the following expressions is not zero?
(a) 0 × 0
(b) 0 + 0
(c) \(\frac{2}{0}\)
(d) \(\frac{0}{2}\)
Solution:
(c) \(\frac{2}{0}\)
Dividing by 0 is not defined.

Question 10.
Which of the following is not true?
(a) (4237 + 5498) + 3439 = 4237 + (5498 + 3439)
(b) (4237 × 5498) × 3439 = 4237 × (5498 × 3439)
(c) 4237 + 5498 × 3439 = (4237 + 5498) × 3439
(d) 4237 × (5498 + 3439) = (4237 × 5498) + (4237 × 3439)
Solution:
(c) 4237 + 5498 × 3439 = (4237 + 5498) × 3439

 Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

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