Students can download 5th Maths Term 3 Chapter 6 Fractions 6.5 Questions and Answers, Notes, Samacheer Kalvi 5th Maths Guide Pdf helps you to revise the complete Tamilnadu State Board New Syllabus, helps students complete homework assignments and to score high marks in board exams.

## Tamilnadu Samacheer Kalvi 5th Maths Solutions Term 3 Chapter 6 Fractions 6.5

Question 1.

Add the following fractions

(i) \(\frac{1}{5}\) + \(\frac{3}{5}\)

Answer:

\(\frac{1}{5}+\frac{3}{5}=\frac{1+3}{5}=\frac{4}{5}\)

(ii) \(\frac{1}{7}\) + \(\frac{3}{7}\)

Answer:

\(\frac{1}{7}+\frac{3}{7}=\frac{1+3}{7}=\frac{4}{7}\)

(iii) \(\frac{5}{12}\) + \(\frac{2}{12}\)

Answer:

\(\frac{5}{12}+\frac{2}{12}=\frac{5+2}{12}=\frac{7}{12}\)

(iv) \(\frac{3}{9}\) + \(\frac{7}{9}\)

Answer:

\(\frac{3}{9}+\frac{7}{9}=\frac{3+7}{9}=\frac{10}{9}\)

(v) \(\frac{2}{15}\) + \(\frac{3}{15}\)

Answer:

\(\frac{2}{15}+\frac{3}{15}=\frac{2+3}{15}=\frac{5}{15}\)

(vi) \(\frac{2}{7}\) + \(\frac{1}{7}\) + \(\frac{3}{7}\)

Answer:

\(\frac{2}{7}+\frac{1}{7}+\frac{3}{7}=\frac{2+1+3}{7}=\frac{6}{7}\)

(vii) \(\frac{3}{10}\) + \(\frac{5}{10}\) + \(\frac{2}{10}\)

Answer:

\(\frac{3}{10}+\frac{5}{10}+\frac{2}{10}=\frac{3+5+2}{10}=\frac{10}{10}=1\)

(viii) \(\frac{2}{9}\) + \(\frac{1}{9}\)

Answer:

\(\frac{2}{9}+\frac{1}{9}=\frac{2+1}{9}=\frac{3}{9}\)

(ix) \(\frac{3}{8}\) + \(\frac{2}{8}\)

Answer:

\(\frac{3}{8}+\frac{2}{8}=\frac{3+2}{8}=\frac{5}{8}\)

Question 2.

Mother gave \(\frac{2}{8}\) of guava to Meena and \(\frac{3}{8}\) of guava to Geetha. How many parts of the guava did she give them altogether?

Answer:

Meena get = \(\frac{2}{8}\)

Geeta get = \(\frac{3}{8}\)

Sum = \(\frac{2}{8}\) + \(\frac{3}{8}\) = \(\frac{5}{8}\)

Question 3.

The girls of Std V cleaned \(\frac{3}{5}\) of a field, while the boys cleaned \(\frac{1}{5}\) part of the field. What part of the field was cleaned altogether?

Answer:

Girls cleaned = \(\frac{3}{5}\)

Boys cleaned = \(\frac{1}{5}\)

Sum = \(\frac{3}{5}+\frac{1}{5}=\frac{4}{5}\)